All categories

2 years ago

What does autosexual mean?

Chemistry

2 answers:

kolezko [41]2 years ago

6 0

Answer:

Autosexuality means people are more attracted to themselves than to others and may prefer masturbation to sex with a partner.

anzhelika [568]2 years ago

5 0

Answer: autosexual people are people who are attracted to themselves rather than other people.

Explanation:

You might be interested in

Which oneeee is ittt!!!!

Marysya12 [62]

Answer:

Disagree.

Explanation:

Nothing would remain. Everything on Earth is made up of atoms. The chair consists of only atoms. So, if you remove all of the atoms, nothing would be left! Hope this helps.

7 0

3 years ago

Read 2 more answers

The law of physics which states that energy can't be created or destroyed but can transfer or change forms is known as

Sedaia [141]

The Law of Conservation of Energy

5 0

3 years ago

Read 2 more answers

I need a background information for this report it's due tomorrow and I'm having difficulty with it please help

Whitepunk [10]

Try using Google Scholar. It'll show you tons of educational resources on topics you look up. Good luck with your report! Hope this helps!

7 0

3 years ago

What is the value of the equilibrium constant at 25 oC for the reaction between the pair: I2(s) and Br-(aq) Give your answer usi

insens350 [35]

Explanation:

Formula to calculate standard electrode potential is as follows.

$E^{o}_{cell} = E^{0}_{cathode} - E^{0}_{anode}$

= 0.535 - 1.065

= - 0.53 V

Also, it is known that relation between $E^{o}_{cell}$ and K is as follows.

$E^{o}_{cell} = \frac{RT}{nF} \times ln K$

ln K = $\frac{nFE^{0}_{cell}}{RT}$

Substituting the given values into the above formula as follows.

ln K = $\frac{nFE^{0}_{cell}}{RT}$

= $\frac{2 \times 96485 C mol^{-1} \times -0.53 V}{8.314 l atm/mol K \times 298 K} \times \frac{1 J}{1 V C}$

ln K = -41.28

K = $e^{-41.28}$

= $1 \times 10^{-18}$

Thus, we can conclude that the value of the equilibrium constant for the given reaction is $1 \times 10^{-18}$ .

5 0

3 years ago

Calculate the percent by mass of 4.35g of Na I dissolved in 105g of water

Ludmilka [50]

<u>We are given:</u>

Mass of Na added = 4.35 grams

Mass of water = 105 grams

<u>Mass Percent of Na:</u>

Total mass of the solution = mass of solute + mass of solvent

Total mass of the solution = 4.35 + 105 = 109.35 grams

Mass percent of solute = (mass of solute / mass of solution) * 100

Mass percent of Solute = (4.35 / 109.35) * 100

Mass percent = 3.978 %

4 0

2 years ago