Answer:
3.54 mol
Explanation:
Step 1: Given data
- Temperature (T): 45.00 °C
Step 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15
K = 45.00°C + 273.15 = 318.15 K
Step 3: Calculate the number of moles (n) of argon gas
We will use the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 2.50 atm × 37.0 L/(0.0821 atm.L/mol.K) × 318.15 K = 3.54 mol
<span>magnesium cations (Mg </span><span>2+</span>) and oxide anions (<span>O 2</span>−<span>)</span>
I'll be using dimensional analysis to help out.
2.5mol Na2O * ( X gNa2O / 1 molNa2O) = ? gNa2O
X gNa2O is the molar mass of the molecule. To find that we must add up the molar masses of all of the elements in the molecule.
There are 2 Na (Sodium).
And 1 O (Oxygen).
The Molar Mass of Na = 2 * 22.99 g/mol (It's multiplied by 2 because there are 2 of them in the molecule)
The Molar mass of O = 16.00 g/mol
If you are confused on where I found them. Let me enlighten you! I found them from a periodic table of elements.
Add those two values together to get a total molecular molar mass of:
38.99g/mol
2.5mol Na2O * ( 38.99 gNa2O / 1 molNa2O) = 97 gNa2O
The correct answer will be C. Carbon and Oxygen because these both are non metals and non metals react colvalently (i.e share electrons) while when metals react with a non metals they react ionically (i.e lose and gain electrons)