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algol [13]
3 years ago
11

What compound is always part of an aqueous solution

Chemistry
2 answers:
const2013 [10]3 years ago
8 0
The compound that is always part of an aqueous solution is NaCI(aq).
Anna [14]3 years ago
3 0
First, an aqueous solution is in which the solvent is Water. 
Some aqueous solutions: Sodium Chloride NaCl, Sodium Hydroxide NaOH, Pepsi, and many others

Hope this Helps :)
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A sample of gas with an initial volume of 12.5 L at a pressure of 784 torr and a temperature of 295 K is compressed to a volume
Kipish [7]

Answer:

Final pressure in (atm) (P1) = 6.642 atm

Explanation:

Given:

Initial volume of gas (V) = 12.5 L

Pressure (P) = 784 torr

Temperature (T) = 295 K

Final volume (V1) = 2.04 L

Final temperature (T1) = 310 K

Find:

Final pressure in (atm) (P1) = ?

Computation:

According to combine gas law method:

\frac{PV}{T} =\frac{P1V1}{T1} \\\\\frac{(784)(12.5)}{295} =\frac{(P1)(2.04)}{310}\\\\33.22 = \frac{(P1)(2.04)}{310}\\\\P1=5,048.18877

⇒ Final pressure (P1) = 5,048.18877 torr

⇒ Final pressure in (atm) (P1) = 5,048.18877 torr / 760

⇒ Final pressure in (atm) (P1) = 6.642 atm

3 0
3 years ago
SELECT ALL THAT APPLY
Luden [163]
The answer is 1 and 3. The number of atoms per molecule of these three substance is not equal. So they will not contain same number of atoms. And for gas, under same condition with same number of moles will have the same volume. The g.f.w is related to the atomic mass. So they are different.
8 0
3 years ago
Read 2 more answers
What is the difference between the number of electrons in an atom of selenium,Se, and the number of electrons in an atom of alum
aliina [53]

Answer:

A)21

Explanation:

To know the difference between the number of electrons in the two atoms, we must first know the number of electrons in the atoms.

For Selenium, Se, we have 34 electrons. The element is in group 6 on the periodic table.

Aluminum on the other hand is in the Boron family with a total of 13 electrons.

The difference,( 34-13) electrons gives a total of 21 electrons

5 0
3 years ago
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How many moles of KCl are required to prepare 1.50 L of 5.4 M KCl?
puteri [66]
5.4 M = moles of solute / 1.50 L 

<span>Multiply both sides by 1.50 L to isolate moles of solute on the right. </span>

<span>8.1 mol = moles of solute </span>


6 0
3 years ago
Read 2 more answers
Calculate the energy required to heat 566.0mg of graphite from 5.2°C to 23.2°C. Assume the specific heat capacity of graphite un
maw [93]

Answer:

7.23 J

Explanation:

Step 1: Given data

  • Mass of graphite (m): 566.0 mg
  • Initial temperature: 5.2 °C
  • Final temperature: 23.2 °C
  • Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹

Step 2: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)

Q = 7.23 J

6 0
3 years ago
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