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3 years ago

How to equally balance CH4 + O2 → H2O + CO2 (Please show work)

Chemistry

2 answers:

grin007 [14]3 years ago

4 0

Answer:

Balanced chemical equation:

CH₄ + 2O₂ → 2H₂O + CO₂

Explanation:

Chemical equation:

CH₄ + O₂ → H₂O + CO₂

Balanced chemical equation:

CH₄ + 2O₂ → 2H₂O + CO₂

Step one:

CH₄ + O₂ → H₂O + CO₂

C = 1 C = 1

H = 4 H = 2

O = 2 O = 3

Step 2:

CH₄ + 2O₂ → H₂O + CO₂

C = 1 C = 1

H = 4 H = 2

O = 4 O = 3

Step 3:

CH₄ + 2O₂ → 2H₂O + CO₂

C = 1 C = 1

H = 4 H = 4

O = 4 O = 4

dimaraw [331]3 years ago

4 0

Answer:

$\huge \boxed{\mathrm{CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O}}$

$\rule[225]{225}{2}$

Explanation:

$\sf CH_4+ O_2 \Rightarrow CO_2 + H_2O$

Balancing the Hydrogen atoms on the right side,

$\sf CH_4+ O_2 \Rightarrow CO_2 +2 H_2O$

Balancing the Oxygen atoms on the left side,

$\sf CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O$

$\rule[225]{225}{2}$

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Explanation:

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2 years ago

A chemist wants to extract copper metal from copper chloride solution. The chemist places 0.50 grams of aluminum foil in a solut

Irina-Kira [14]

Answer:

Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.

Explanation:

It is a stichiometry problem.

We should write the balance equation of the mentioned chemical reaction:

2Al + 3CuCl₂ → 3Cu + 2AlCl₃.

It is clear that 2.0 moles of Al foil reacts with 3.0 moles of CuCl₂ to produce 3.0 moles of Cu metal and 2.0 moles of AlCl₃.

Also, we need to calculate the number of moles of the reported masses of Al foil (0.50 g) and CuCl₂ (0.75 g) using the relation:

n = mass / molar mass

The no. of moles of Al foil = mass / atomic mass = (0.50 g) / (26.98 g/mol) = 0.0185 mol.

The no. of moles of CuCl₂ = mass / molar mass = (0.75 g) / (134.45 g/mol) = 5.578 x 10⁻³ mol.

From the stichiometry Al foil reacts with CuCl₂ with a ratio of 2:3.

∴ 3.85 x 10⁻³ mol of Al foil reacts completely with 5.578 x 10⁻³ mol of CuCl₂ with (2:3) ratio and CuCl₂ is the limiting reactant while Al foil is in excess.

From the stichiometry 3.0 moles of CuCl₂ will produce the same no. of moles of copper metal (3.0 moles).
So, this reaction will produce 5.578 x 10⁻³ mol of copper metal.
Finally, we can calculate the mass of copper produced using:

mass of Cu = no. of moles x Atomic mass of Cu = (5.578 x 10⁻³ mol)(63.546 g/mol) = 0.354459 g ≅ 0.36 g.

So, the answer is:

Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.

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3 years ago

Which of the following sets of inputs and outputs can be used to describe photosynthesis?

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3 years ago

An electrochemical cell is constructed with a zinc metal anode in contact with a 0.052 M solution of zinc nitrate and a silver c

lana [24]

Answer:

Q = 12.38

Explanation:

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The reaction quotient, Q in a reaction, is the product of the concentrations of the products divided by the product of the concentrations of the reactants.

In an electrochemical cell, Q is the ratio of the concentration of the electrolyte at the anode to that of the electrolyte at the cathode.

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