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3 years ago

Find the 15th term of the arithmetic sequence.

Mathematics

2 answers:

krek1111 [17]3 years ago

7 0

The answer is
c. 15a + 1

Aneli [31]3 years ago

5 0

It's all about matching patterns.

The coefficient of "a" in the given sequence is the term number (1, 2, 3, ...) and the constant remains constant at 1. Thus the 15th term can be expected to be ...
c. 15a + 1

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The coordinates of point Care A. (3,-1) B. (1, -3) C. (3,1) D. (-3,1) E. (-3,-1)

Mars2501 [29]

D (-3,1) hopes this helps

4 0

2 years ago

What substitution should be used to rewrite 16(x3 + 1)2 – 22(x3 + 1) – 3 = 0 as a quadratic equation?

Vesna [10]

Answer:

z = x^3 +1

Step-by-step explanation:

Noting the squared term, it makes sense to substitute for that term:

z = x^3 +1

gives ...

16z^2 -22z -3 = 0 . . . . the quadratic you want

_____

Solutions derived from that substitution

Factoring gives ...

16z^2 -24z +2z -3 = 0

8z(2z -3) +1(2z -3) = 0

(8z +1)(2z -3) = 0

z = -1/8 or 3/2

Then we can find x:

x^3 +1 = -1/8

x^3 = -9/8 . . . . . subtract 1

x = (-1/2)∛9 . . . . . one of the real solutions

x^3 +1 = 3/2

x^3 = 1/2 = 4/8 . . . . . . subtract 1

x = (1/2)∛4 . . . . . . the other real solution

The complex solutions will be the two complex cube roots of -9/8 and the two complex cube roots of 1/2.

7 0

3 years ago

Read 2 more answers

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allsm [11]

Ron had 140 picture cards more than Ben

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Find the midpoint of the line segment defined by the points: (5, 4) and (−2, 1) (2.5, 1.5) (3.5, 2.5) (1.5, 2.5) (3.5, 1.5)

Setler79 [48]

Answer:

$\boxed {\boxed {\sf (1.5 , 2.5)}}$

Step-by-step explanation:

The midpoint is the point that bisects a line segment or divides it into 2 equal halves. The formula is essentially finding the average of the 2 points.

$(\frac {x_1+x_2}{2}, \frac {y_1+ y_2}{2})$