The answer is 67.82 g/mol
Oh no se, aparte que ni inglés se lo siento 0102938
A solvent is something that can have something else dissolved within it and turn into a homogenous solution, while the solute is that something else that can be dissolved into the solvent. Usually, the solvent is found in greater amount because most (except for rare cases) solvents have a saturation point that is below the equal-mass point.
Answer:
See explanation
Explanation:
If heat is given out in a reaction, then that reaction is exothermic. If heat is absorbed in a reaction, then that reaction is endothermic.
Hence, if heat is given out, the reaction is exothermic. The heat given out does work on the surrounding thus the laws of conservation of energy are obeyed.
Answer : The rate law for formation of NOBr based on this mechanism is, ![\frac{k_1\times k_2}{k_1^-}[Br_2][NO]^2](https://tex.z-dn.net/?f=%5Cfrac%7Bk_1%5Ctimes%20k_2%7D%7Bk_1%5E-%7D%5BBr_2%5D%5BNO%5D%5E2)
Explanation :
The overall reaction is:
Rate law = ![k[Br_2][NO]^2](https://tex.z-dn.net/?f=k%5BBr_2%5D%5BNO%5D%5E2)
The first step of the overall reaction is:
Rate law 1 = ![k_1[Br_2][NO]](https://tex.z-dn.net/?f=k_1%5BBr_2%5D%5BNO%5D)
Rate law 2 = ![k_1^-[NOBr_2]](https://tex.z-dn.net/?f=k_1%5E-%5BNOBr_2%5D)
The second step of the overall reaction is:
Rate law 3 = ![k_2[NOBr_2][NO]](https://tex.z-dn.net/?f=k_2%5BNOBr_2%5D%5BNO%5D)
Now rate law of overall reaction can be obtained as follows.
We are multiplying rate law 1 and rate law 3 and dividing by rate law 2, we get:
Rate law = ![\frac{[k_1[Br_2][NO]]\times [k_2[NOBr_2][NO]]}{[k_1^-[NOBr_2]]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Bk_1%5BBr_2%5D%5BNO%5D%5D%5Ctimes%20%5Bk_2%5BNOBr_2%5D%5BNO%5D%5D%7D%7B%5Bk_1%5E-%5BNOBr_2%5D%5D%7D)
Rate law =
Rate law =
The rate law for formation of NOBr based on this mechanism is,
