All categories

3 years ago

In what type of job might being a difficult person not be much of a liability ?

1 answer:

7 0

A possible answer would be a stocker. a person who sorts thing or delivery person who just drops things off. there are little to no jobs with no human interaction. some good options for jobs where you work by yourself are:
Embalmer.Accountant.Travel Photographer.Tree Planter.Freelance Writer.Truck Driver.Data Scientist.Taxidermist. I HOPE THIS HELPS!!!

You might be interested in

Two cars go through 2 different crashes. Car 1 experiences a 500 Ns impulse for a duration of 15s, while car 2 experiences that

tatuchka [14]

B is your answer hope this helps;)

5 0

3 years ago

a person throws a ball upward into the air with an initial velocity of 20 m/s. calculate (a) how high it goes, and (b) how long

Phantasy [73]

Answer:

a) about 20.4 meters high

b) about 4.08 seconds

Explanation:

Part a)

To find the maximum height the ball reaches under the action of gravity (g = 9.8 m/s^2) use the equation that connects change in velocity over time with acceleration.

$a=\frac{Vf-Vi}{t}$

$-9.8 \frac{m}{s} =\frac{Vf-Vi}{t}$

In our case, the initial velocity of the ball as it leaves the hands of the person is Vi = 20 m/s, while thw final velocity of the ball as it reaches its maximum height is zero (0) m/s. Therefore we can solve for the time it takes the ball to reach the top:

$-9.8 =\frac{0-20}{t}\\t=\frac{20}{9.8} s = 2.04 s$

Now we use this time in the expression for the distance covered (final position Xf minus initial position Xi) under acceleration:

$Xf-Xi=Vi*t+\frac{1}{2} a t^{2} \\Xf-Xi=20*(2.04)-\frac{1}{2} 9.8*2.04^{2}\\Xf-Xi=20.408 m$

Part b) Now we use the expression for distance covered under acceleration to find the time it takes for the ball to leave the person's hand and come back to it (notice that Xf-Xi in this case will be zero - same final and initial position)

$Xf-Xi=0=20*(t)-\frac{1}{2} 9.8*t^{2$

To solve for "t" in this quadratic equation, we can factor it out as shown:

$0= t(20-\frac{9.8}{2} t)$

Therefore there are two possible solutions when each of the two factors equals zero:

1) t= 0 (which is not representative of our case) , and

2) the expression in parenthesis is zero:

$0= 20-\frac{9.8}{2} t\\t=\frac{20*2}{9.8} = 4.08 s$

7 0

3 years ago

What is the KE if a 10kg mass traveling at 5 m/s

11111nata11111 [884]

Answer: KE = 25 J

Explanation: You must use the formula

KE = 1/2 m v²

to solve this problem.

KE = 1/2 (10 Kg) (5 m/s)

KE = 1/2 (50 kgm/s)

KE = 25 J

7 0

2 years ago

If length of wire is doubled keeping the diameter constant ,its Youngs modulus will be

Luda [366]

Answer:

Y = Stress / Strain = (F / A) / (l / L) where l is the change in length

Since L is doubled and A remains the same one would expect l, the change in length to also double so Y remains the same.

As an example think of hanging a weight from a spring and the same weight from a similar spring of twice the length - one would expect the longer spring to show twice the extension of the shorter spring.

3 0

2 years ago

Why is water known as the "Universal Solvent"?

kompoz [17]

Water is known as the universal solvent because it is capable of dissolving a variety of substances, more than any other liquid.

Hope this helps!

4 0

3 years ago