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MaRussiya [10]
3 years ago
15

5.

Physics
2 answers:
lozanna [386]3 years ago
6 0

Answer:

(1)

Explanation:

iris [78.8K]3 years ago
3 0

Answer:

the answer is a time your welcome

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Water is discharged from a pipeline at a velocity v (in ft/sec) given by v = 1306p(1/2), where p is the pressure (in psi). If th
shepuryov [24]

Answer:

a=38.5 ft/sec^{2}

Explanation:

Note that acceleration is the rate change of velocity i.e

acceleration=\frac{change in velocity}{change in time}\\a=\frac{dv}{dt} \\.

Since the velocity is giving as a variable dependent on the pressure, we have to differentiate implicitly both side with respect to time,i.e

\frac{dv}{dt}=1306*(1/2)p^{-1/2}\frac{dp}{dt} \\

if we substitute value for the pressure as giving in the question and also since the rate change of pressure is 0.354psi/sec, we have

a=653*0.1667*0.354\\

a=\frac{dv}{dt}=653(36)^{-1/2}*0.354\\  a=38.5 ft/sec^{2}

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a man can swim in still water with speed of 2kmhr-1 wants to cross a river 200m wide flowing with 1kmhr-1 . Calculate the time t
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d savage

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