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Reika [66]
3 years ago
7

Given PQR ~ JKL solve for X

Mathematics
2 answers:
Naya [18.7K]3 years ago
4 0
The answer would be x=4
Sergeeva-Olga [200]3 years ago
3 0
The answer would be 4



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Answer: x - 3y = -2
x = -2 + 3y

x - 3y = 16
x = 16 + 3y

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A puppy named Peanut started out at 2 pounds and gained 1 pound every month. At how many months did Peanut weigh 7 pounds?
Alex777 [14]

Answer:


Step-by-step explanation:


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Hey! i’ll give brainliest please help
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Answer: The last choice

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External conflict includes

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3 years ago
Verify that the following function is a probability mass function, and determine the requested probabilities. f left-parenthesis
Licemer1 [7]

Answer:

f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3

1) f(x_i) \geq 0, \forall x_i

2) sum_{i=1}^n P(X_i) =1

We can find the individual probabilities and we got:

f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923

f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307

f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

P(X \leq 1) = P(X=1) =0.6923

P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077

P(2

Step-by-step explanation:

For this case we have the following density function:

f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3

In order to satisfty that this function is a probability mass function we need to check two conditions:

1) f(x_i) \geq 0, \forall x_i

2) sum_{i=1}^n P(X_i) =1

We can find the individual probabilities and we got:

f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923

f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307

f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

And if we want to find the following probabilities:

P(X \leq 1) = P(X=1) =0.6923

P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077

P(2

7 0
2 years ago
Please help my assignment is missing and I really need to finish it.
photoshop1234 [79]

Answer: it is D

Step-by-step explanation:

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2 years ago
Read 2 more answers
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