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lina2011 [118]
3 years ago
6

A student wants to draw a model of an atom. Which statement describes how to find the number of neutrons to include in the model

?
A.) Subtract the atomic number from the mass number.
B.) Add the atomic number and the mass number.
C.) Add the number of electrons to the number of protons.
D.) Subtract the number of electrons from the number of protons.
Chemistry
1 answer:
san4es73 [151]3 years ago
4 0

c is the correct answer

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What is the only nonmetal in group 14?
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Answer:

The only nonmetal in group 14 is carbon.

Explanation:

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The energy released from 1 gram of uranium is more than 1 million times greater than the energy released from 3 grams of coal. T
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The energy released from 1 gram of uranium is more than 1 million times greater than the energy released from 3 grams of coal is True.

<u>Explanation:</u>

Nuclear Fission is the process in which splitting of a nucleus takes place that releases free neutrons and lighter nuclei. The fission of heavy elements like "Uranium is highly exothermic" and releases "200 million eV" compared to the energy that is released by burning coal which gives a few eV.

In the given example, it is obvious that the energy released from 1 gram of uranium is more than that of the energy released from 3 grams of coal because the amount of energy released during nuclear fission is millions of times more efficient per mass than that of coal considering only \frac{1}{10}^{th} part of the original nuclei is converted to energy.

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3 years ago
Calculate the ph of a 0.17 m solution of c6h5nh3no3 (kb for c6h5nh2 = 3.8 x 10-10). record your ph value to 2 decimal places.
MatroZZZ [7]
<span>Mass of the solution = 0.17m
 Kb for C6H5NH2 = 3.8 x 10^-10
 We know Ka for C6H5NH2 = 1.78x10^-11
  We have Kw = Ka x Kb => Ka = Kw / Kb
  => (C2H5NH2)(H3O^+)/(C2H5NH3^+) => 1.78x10^-11 = K^2 / 0.17
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6 0
3 years ago
Calculate the number of moles of gas in the following at STP: 45.6 L of H2 gas
zimovet [89]

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2.04 mol

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At STP, 1 mole = 22.4 L

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8 0
3 years ago
A student is asked to determine the molarity of a strong base by titrating it with 0.250 M solution of H2SO4. The students is in
tamaranim1 [39]

Answer:

The molarity of the strong base is 0.625 M

Which procedural error will result in a strong base molarity that is too high?

⇒ Using a buret with a tip filled with air rather than the H2SO4 solution

Explanation:

<u>Step 1:</u> Data given

Molarity of H2SO4 = 0.250 M

The initial buret reading is 5.00 mL

The final reading is 30.00 mL

<u />

<u>Step 2:</u> Calculate volume of H2SO4 used

30.00 mL - 5.00 mL = 25.00 mL

<u>Step 3:</u> Calculate moles of H2SO4

0.250 M = 0.250 mol/L

Since there are 2 H+ ions per H2SO4

0.250 mol/L  * 2 = 0.500 mol/L

The number of moles H2SO4 = 0.500 mol/L * 0.025 L

Number of moles H2SO4 = 0.0125 mol

<u>Step 4</u>: Calculate moles of OH-

For 1 mol H2SO4, we need 1 mol of OH-

For 0.0125 mol of H2SO4, we have 0.0125 mol of OH-

<u>Step 5</u>: Calculate the molarity of the strong base

Molarity = moles / volume

Molarity OH- = 0.0125 mol / 0.02 L

Molarity OH - = 0.625 M

Which procedural error will result in a strong base molarity that is too high?

⇒ Using a buret with a tip filled with air rather than the H2SO4 solution

   

5 0
3 years ago
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