All categories

2 years ago

What is the name of CF4?.

Chemistry

2 answers:

Mumz [18]2 years ago

8 0

Answer:

please mark me as brainlest

Explanation:

carbon fluoride is the answers

Semenov [28]2 years ago

4 0

Answer:

Tetrahedral.

Explanation:

CF4, as can be seen, has only one carbon atom and four fluorine atoms. The most preferred shape of the chemical is therefore, tetrahedral.

You might be interested in

What is the electron configuration of Mn3+

Mumz [18]

Answer:

The electron configuration for a

Mn3+ ion is [Ar]3d4

Explanation:

4 0

3 years ago

Balance this equation and pick the answer with the coefficients that belong there.

geniusboy [140]

Answer:

2,3,6,1

Explanation:

The unbalanced reaction expression is given as:

AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃

We need to balanced this reaction equation. Our approach is a mathematical method where we assign variable a,b,c and d as the coefficients.

aAlBr₃ + bK₂SO₄ → cKBr + dAl₂(SO₄)₃

Conserving Al; a = 2d

Br: 3a = c

K: 2b = c

S: b = 3d

O: 4b = 12d

Let a = 1, c = 3, d = $\frac{1}{2}$ b = $\frac{3}{2}$

Multiply through by 2 to give;

a = 2, b = 3, c = 6 and d = 1

2AlBr₃ + 3K₂SO₄ → 6KBr + Al₂(SO₄)₃

6 0

2 years ago

S<br> SIO₂ +3C Sic +20o<br> Sic ? mass in grams<br> С c-

seraphim [82]

Answer:

26.74g

Explanation:

The equation of the reaction is;

SIO₂ + 3C --> SiC +2CO

From the balanced equation, the relationship between SiC and C is;

3 mol of C produces 1 mol of SiC

Converting mol to mass using; Mass = moles * Molar mass

Mass of SiC = 1 mol * 40.11 g/mol = 40.11g

This means;

3 mol of C produces 40.11g of SiC

2 mol of C produces xg of SiC

3 = 40.11

2 = x

x = 2 * 40.11 / 3 = 26.74g

6 0

3 years ago

The vapor pressure of benzene is 73.03 mm Hg at 25°C. How many grams of estrogen (estradiol), C18H24O2, a nonvolatile, nonelectr

alexira [117]

Answer:

14.9802 grams of estrogen must be added to 216.7 grams of benzene.

Explanation:

The relative lowering of vapor pressure of solution containing non volatile solute is equal to mole fraction of solute.

$\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}$

Where:

$p_o$ = Vapor pressure of pure solvent

$p_s$ = Vapor pressure of the solution

$n_1$ = Number of moles of solvent

$n_2$ = Number of moles of solute

$p_o = 73.03 mmHg$

$p_s= 71.61 mmHg$

$n_1=\frac{216.7 g}{78.12 g/mol}=2.7739 mol$

$\frac{73.03 mmHg-71.61 mmHg}{73.03 mmHg}=\frac{n_2}{2.7739 mol+n_2}$

$n_2=0.05499 mol$

Mass of 0.05499 moles of estrogen :

= 0.05499 mol × 272.4 g/mol = 14.9802 g

14.9802 grams of estrogen must be added to 216.7 grams of benzene.

6 0

3 years ago

PLEASE HELP ASAP

Lapatulllka [165]

Answer:

See explanation

Explanation:

We must first write the equation of the reaction as follows;

C3H8 + 5O2 ----> 3CO2 + 4H2O

Now;

We obtain the number of moles of C3H8 = 132.33g/44g/mol = 3 moles

So;

1 mole of C3H8 yields 3 moles of CO2

3 moles of C3H8 yields 3 × 3/1 = 9 moles of CO2

We obtain the number of moles of oxygen = 384.00 g/32 g/mol = 12 moles

So;

5 moles of oxygen yields 3 moles of CO2

12 moles of oxygen yields 12 × 3/5 = 7.2 moles of CO2

We can now decide on the limiting reactant to be C3H8

Therefore;

Mass of CO2 produced = 9 moles of CO2 × 44 g/mol = 396 g of CO2

Again;

1 moles of C3H8 yields 4 moles of water

3 moles of C3H8 yields 3 × 4/1 = 12 moles of water

Hence;

Mass of water = 12 moles of water × 18 g/mol = 216 g of water

In order to obtain the percentage yield from the reaction, we have;

b) Actual yield = 269.34 g

Theoretical yield = 396 g

Therefore;

% yield = actual yield/theoretical yield × 100/1

Substituting values

% yield = 269.34 g /396 g × 100

% yield = 68%

8 0

3 years ago