Let x=the first number
Then x+7=second number
And 4(x+7)+2=third number (2 more than 4 times the second)
Now we are told that:
x+(x+7)+(4(x+7)+2)=85 get rid of parentheses
x+x+7+4x+28+2=85 simplify
6x+37=85 subtract 37 from each side
6x+37-37=85-37
6x=48
x=8---first number
x+7=8+7=15 second number
4(x+7)+2=4*15+2=62 third number
CK
8+15+62=85
85=85
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Answer:
Step-by-step explanation:
Given that according to the U.S. Census Bureau, the prob ability that a randomly selected household speaks only English at home is 0.81.
The probability that a randomly selected household speaks only Spanish at home is 0.12.
(a) the probability that a randomly selected household speaks only English or only Spanish at home
= 0.81+0.12 = 0.93
(since these two are disjoint sets)
(b) the probability that a randomly selected household speaks a language other than only English or only Spanish at home
= 1-0.93= 0.07 (remaining)
(c) the probability that a randomly selected household speaks a language other than only English at home
=1-0.81=0.19
(d) Can the probability that a randomly selected household speaks only Polish at home equal 0.08? Why or why not?
Polish alone can never exceed 1-(0.81+0.12) i.e. 0.70
At most it can take values as 0.7 only
So no is the answer.
