Explanation:
It is given that, the field near a typical pulsed-field machine rises from 0 T to 2.5 T in 200 μs
Change in magnetic field, 
Change in time, 
Diameter, d = 2.3 cm
Radius, r = 0.0115 m
Emf is induced in the ring as the field changes. It is given by :
E = 5.19 volts
So, the emf induced in the ring is 5.19 volts. Hence, this is the required solution.
When light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.
To find the answer, we have to know about the rules followed by drawing ray-diagram.
<h3>What are the rules obeyed by light rays?</h3>
- If the incident ray is parallel to the principal axis, the refracted ray will pass through the opposite side's focus.
- The refracted ray becomes parallel to the major axis if the incident ray passes through the focus.
- The refracted ray follows the same path if the incident light passes through the center of the curve.
Thus, we can conclude that, when light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.
Learn more about refraction by a lens here:
brainly.com/question/13095658
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An VIRTUAL image cannot be projected, and
forms where light rays appear to originate.
Answer:
We could get the time taken by the ball to return back to earth, using the formula:
s = u t + ½ a t², where
s = displacement of the body moving with initial velocity u, acceleration 'a' in time t.
In the present case s=0 (as the ball returns back to starting time)
u= 30 m/s; a = -10 m/s² ( negative sign as a is in opposite direction to u); t=?
0 = 30 t - ½ ×10 ×t²; ==> 5 t = 30, t= 6 second.
So ball will return back after 6 second after being thrown up.
Explanation:
I looked it up
Hope this helps
Speed, v = fλ.
Where f is the frequency in Hertz, wavelength is in meters.
Speed, v = 2*5 = 10
Speed = 10 m/s.
