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Reptile [31]
2 years ago
5

Complete the following:

Physics
1 answer:
masha68 [24]2 years ago
8 0

When light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.

To find the answer, we have to know about the rules followed by drawing ray-diagram.

<h3>What are the rules obeyed by light rays?</h3>
  • If the incident ray is parallel to the principal axis, the refracted ray will pass through the opposite side's focus.
  • The refracted ray becomes parallel to the major axis if the incident ray passes through the focus.
  • The refracted ray follows the same path if the incident light passes through the center of the curve.

Thus, we can conclude that, when light is incident parallel to the principal axis and then strikes a lens, the light will refract through the focal point on the opposite side of the lens.

Learn more about refraction by a lens here:

brainly.com/question/13095658

#SPJ1

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Y = v0t + 1/2gt^2.
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A hot water stream at 80 oC enters a mixing chamber with mass flow rate of 3.6 kg/s and mixed with cold water at 20 oC. If the m
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Explanation:

The mixing chamber will be well insulated when steady operating conditions exist such that there will be negligible heat loss to the surroundings. Therefore, changes in the kinetic and potential energies of the fluid streams will be negligible and there are constant fluid properties with no work interactions.

   T < T_{sat} at 250 kPa = 127.41^{o}C

   h_{1} approx equal to h_{f} at 80^{o}C

              = 335.02 kJ/kg

    h_{2} ≈ h_{f} at 20^{o}C

                      = 83.915 kJ/kg

and,    h_{3} ≈ h_{f} at 42^{o}C = 175.90 kJ/kg

Therefore, mass balance will be calculated as follows.

   m^{o}_{in} - m^{o}_{out} = \Delta m^{o}_{system} \rightarrow m^{o}_{1} + m^{o}_{2} = m^{o}_{3}

And, energy balance will be given as follows.

      E^{o}_{in} - E^{o}_{out} = \Delta E^{o}_{system}

As we are stating steady conditions,

     \Delta m^{o}_{system} and \Delta E^{o}_{system} cancel out to zero.

So,    E^{o}_{in} = E^{o}_{out}

     m^{o}_{1}(h_{1}) + m^{o}_{2}(h_{2}) = m^{o}_{3}(h_{3})

On combining the relations, we solve for m^{o}_{2} as follows.

   m^{o}_{1}(h_{1}) + m^{o}_{2}(h_{2}) = (m^{o}_{1} + m^{o}_{2})(h_{3})

   m^{o}_{2} = (\frac{(h_{1} - h_{3})}{(h_{3} - h_{2})}) \times m^{o}_{1}

              = \frac{(335.02 - 175.90)}{(175.90 - 83.915)} \times 0.5  

       m^{o}_{2} = 0.865 kg/s

                       = 51.9 kg/min      (as 1 min = 60 sec)

Thus, we can conclude that the mass flow rate of cold stream is 51.9 kg/min.

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3 years ago
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