Question

What is the concentration of k+ ions in a 0.045 m k2co3 solution assuming complete dissociation?express the concentration in molarity?

Answer 1

Answer: The concentration of $K^+$ ions in the solution is 0.09 M

Explanation:

We are given:

Concentration of $K_2CO_3$ = 0.045 M

The chemical equation for complete dissociation of potassium carbonate follows:

$K_2CO_3(aq.)\rightarrow 2K^+(aq.)+CO_3^{2-}(aq.)$

By stoichiometry of the reaction:

1 mole of potassium carbonate produces 2 moles of potassium ions and 1 mole of carbonate ions.

So, the concentration of potassium ions in the given solution = $(2\times 0.045M)=0.09M$

Hence, the concentration of $K^+$ ions in the solution is 0.09 M

Answer 2

(0.045) x (2 K{+} ions / 1 molecule K2CO3) = 0.090 in whatever units the original concentration was expressed in