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Hoochie [10]
3 years ago
7

How much does 3 moles of silica weigh

Chemistry
1 answer:
amm18123 years ago
6 0

84.2565

Because

1 silica is equal to 28.0855,

times 3 is 84.2565

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What is the 4 methods that can be used to separate mixtures?
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3 0
3 years ago
Which of the following is a chemical change?
avanturin [10]
C is the answer because that is an actual chemical change where the sulfur and iron are not separate from each other anymore
8 0
3 years ago
Read 2 more answers
6. Write the ICE chart for the reaction of 32.0 g of sulfur and 71.0 g of chlorine: S8 + 4 Cl24S2Cl2 After completing the chart
Marianna [84]

Answer:

ICE Table Figure

a. 67.37 g S_2Cl_2

b. 35.62 g Cl_2

c. 58.61 gS_2Cl_2

Explanation:

For the <u>ICE table </u>we have to keep in mind that we have 4 moles of Cl_2 and 1 mol of S_8 and the reactives are consumed, so for Cl_2 we will have -4X and for S_8 we will have -X. Follow the same logic we will have -4X for S_2Cl_2.

a. <u>Mass of the product</u>

Molar mass of S_8= 256.52 g/mol

Molar mass of Cl_2=70.9 g/mol

Molar mass of S_2Cl_2=135.03 g/mol

We have to find the limiting reagent in the reaction:

S_8+4Cl_2->4S_2Cl_2

\frac{32}{256.52}=0.124molS_8

\frac{71}{70.9}=1 molCl_2

Divide by the coefficients in the balanced reaction:

\frac{0.124}{1}=0.124mol

\frac{1}{4}=0.25 mol

The limiting reagent would be S_8

Now is posible to calculate the amount of S_2Cl_2 produced:

0.124molS_8\frac{4molS_2Cl_2}{1 molS_8}\frac{135.03gS_2Cl_2}{1 molS_2Cl_2}=67.37gS_2Cl_2

b. <u>Mass  in excess</u>

0.124molS_8\frac{4molCl_2}{1 molS_8}\frac{70.9gCl_2}{1 molCl_2}=35.38gCl_2

Excess\hspace{0.1cm}=\hspace{0.1cm}71gCl_2-35.38gCl_2=35.62 gCl_2

C. <u>87%Yield</u>

67.37gS_2Cl_2\frac{87}{100}=58.61gS_2Cl_2

5 0
3 years ago
What is the correct defination for carbon tetrachloride
V125BC [204]

B - CCL4

This is because it doesn't say Dicarbon or any of that sort, so Carbon is alone. This immediately eiminates the option of C.

A is incorrect as it has Chlorine first rather than Carbon, so that's also incorrect.

D is incorrect as 7 is hepta rather than tetra.

The list is as so;

Mono - 1; Di - 2; Tri - 3; Tetra - 4; Penta - 5; Hexa - 6; Hepta - 7; Octa - 8; Nona - 9; Deca - 10.

Hope this helps!

5 0
3 years ago
The 1995 Nobel Prize in chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work concerning th
Nikolay [14]

Answer:

\Delta H_{rxn3}=-162.5 kJ/mol

Explanation:

The reaction we need to calculate:

O_3 (g) + Cl (g) \longrightarrow ClO (g) + O_2 (g)

1) O_3 (g) + ClO (g) \longrightarrow Cl (g) +2 O_2 (g)

\Delta H_{rxn}=-122.8 kJ/mol

We need the ClO in the products side, so we use the inverse of this reaction:

Cl (g) +2 O_2 (g) \longrightarrow O_3 (g) + ClO (g)

\Delta H_{rxn1}=122.8 kJ/mol

2) 2 O_3 (g) \longrightarrow 3 O_2 (g)

\Delta H_{rxn2}=-285.3 kJ/mol

Now we need to combine this two:

Cl (g) +2 O_2 (g) + 2 O_3 (g)\longrightarrow O_3 (g) + ClO (g) + 3 O_2 (g)

Cl (g) + O_3 (g)\longrightarrow ClO (g) + O_2 (g)

The enthalpy of reaction:

\Delta H_{rxn3}=\Delta H_{rxn1}+ \Delta H_{rxn2}=122.8 kJ/mol-285.3 kJ/mol

\Delta H_{rxn3}=-162.5 kJ/mol

4 0
3 years ago
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