1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Reil [10]
3 years ago
12

You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from

25.10°C to 27.78° C. What is the molar enthalpy of neutralization of the acid in kJ/mol? Assume all densities are 1.00 g/mL and the specific heat capacities are 4.184 J/g*K.
Chemistry
1 answer:
GuDViN [60]3 years ago
8 0

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol

The balanced chemical reaction will be,

HCl+NaOH\rightarrow NaCl+H_2O

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = 200mL+200L=400mL

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g

Now we have to calculate the heat absorbed during the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

c = specific heat of water = 4.18J/g^oC

m = mass of water = 400 g

T_{final} = final temperature of water = 27.78^oC=273+25.10=300.78K

T_{initial} = initial temperature of metal = 25.10^oC=273+27.78=298.1K

Now put all the given values in the above formula, we get:

q=400g\times 4.18J/g^oC\times (300.78-298.1)K

q=4480.96J

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

You might be interested in
What are the two basic ways in which ions form from atoms?
andrew-mc [135]

Answer:

An ion is an atom or group of atoms that has an electric charge. When an atom loses an electron, it loses a negative charge and becomes a positive ion. When an atom gains an electron, it gains a negative charge and becomes a negative ion. a sodium ion forms when a sodium atom loses one electron and becomes positively charged. a chloride ion forms when a chlorine atom gains one electron and becomes negatively charged.

Hope this helps,

      Arabella

4 0
3 years ago
For+the+reaction+H2+++I2+-+2HI+the+equilibrium+constant,+kc+is+49+at+a+fixed+temperature.+Two+mole+of+hydrogen+and+two+moles+of+
Sonja [21]

Answer : The initial concentration of HI and concentration of HI at equilibrium is, 0.27 M and 0.386 M  respectively.

Solution :  Given,

Initial concentration of H_2 and I_2 = 0.11 M

Concentration of H_2 and I_2 at equilibrium = 0.052 M

Let the initial concentration of HI be, C

The given equilibrium reaction is,

    H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

Initially               0.11   0.11            C

At equilibrium  (0.11-x) (0.11-x)   (C+2x)

As we are given that:

Concentration of H_2 and I_2 at equilibrium = 0.052 M  = (0.11-x)

The expression of K_c will be,

K_c=\frac{[HI]^2}{[H_2][I_2]}

54.3=\frac{(C+2(0.058))^2}{(0.052)\times (0.052)}

By solving the terms, we get:

C = 0.27 M

Thus, initial concentration of HI = C = 0.27 M

Thus, the concentration of HI at equilibrium = (C+2x) = 0.27 + 2(0.058) = 0.386 M

3 0
3 years ago
What are chemical symbols and chemical formulas used for
lozanna [386]

Answer:

chemicals symbols are used for abbreviating the name of the element/chemical  while chemicals formulas tell you how much of each element are in each chemical atom

Explanation:

4 0
3 years ago
An INPUT of photosynthesis is ______________<br> A.Oxygen<br> B.Roots<br> C.Sunlight
AfilCa [17]

The inputs of photosynthesis are light energy, and matter in the form of water absorbed through the roots, and carbon dioxide absorbed through the leaves.

Therefore an input of photosynthesis from the choices given is,

Sunlight

3 0
3 years ago
Read 2 more answers
Which phrases accurately describe this rock. check all that apply
Nina [5.8K]
What are the phrases I don’t see any pictures??
7 0
3 years ago
Other questions:
  • 200 ml of a 0.500 m ca(no3)2 solution was made, but only 150 ml of solution are needed. if you pour out 50 ml of the soultion, w
    14·1 answer
  • Sodium is produced by electrolysis of molten sodium chloride. what are the products at the anode and cathode, respectively?
    15·1 answer
  • What is the mass of a neutron?
    13·2 answers
  • Use molecular orbital theory to determine whether f22+ is paramagnetic or diamagnetic.
    13·2 answers
  • (14.01+320)*(41.9/2)
    9·2 answers
  • if you help me ill give you more brainly's. plzz help.At 1 atm, how much energy is required to heat 37.0 g of H2O(s) at –10.0 °C
    6·1 answer
  • What is the boiling point (in °C) of a 0.743 m aqueous solution of KCI?
    8·1 answer
  • What is the number of valence electrons in a calcium atom? * 8 2 18 20​
    10·1 answer
  • WILL GIVE BRAINLIEST!!!
    8·1 answer
  • How does gravity affect the rain during a rainstorm?
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!