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evablogger [386]
3 years ago
14

Question 4 (1 point)

Mathematics
1 answer:
kow [346]3 years ago
8 0

Answer:

pretty sure its A n B = {1,5}

Step-by-step explanation:

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The pickerington girls track team ran a 4 by 100 meter relay in 48.9 seconds. If four girls ran the race how fast did each girl
Oduvanchick [21]
48.9 / 4 = 12.225
distance = 100m
time = 12.225 sec
v = d/t
The answer is 8.1799
5 0
3 years ago
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Hey Guys! I need some help. This is the question... Sara travels often for her job. The miles she traveled for the last seven wo
Schach [20]

Using the median concept, it is found that the interquartile range of Sara's daily miles is of 21 miles.

<h3>What are the median and the quartiles of a data-set?</h3>

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.
  • The interquartile range is the difference of the quartiles.

The ordered data-set is given as follows:

65, 72, 86, 88, 91, 93, 97

There are 7 elements, hence the median is the 4th element, of 88. Then:

  • The first half is 65, 72, 86.
  • The second half is 91, 93, 97.

Since the quartiles are the medians of each half, the have that:

  • The first quartile is of 72 miles.
  • The third quartile is of 93 miles.
  • The interquartile range is of 93 - 72 = 21 miles.

More can be learned about the median of a data-set at brainly.com/question/3876456

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4 0
2 years ago
The system of equations is graphed on the coordinate plane.
ehidna [41]

Answer: The solution is (3, -2)

This means that x = 3 and y = -2 pair up together.

=====================================================

Explanation:

The solution is where the two lines cross. Note if we started at the origin (0,0) and moved to the right 3 units, and then down 2 units, we would arrive at the location (3, -2).

-----------------

As a way to check, we can plug x = 3 into each equation. We should get y = -2 as a result for each equation

y = (-5/3)x + 3

y = (-5/3)*3 + 3

y = -5+3

y = -2

The first equation is confirmed. Let's check the second equation

y = (1/3)x - 3

y = (1/3)*3 - 3

y = 1 - 3

y = -2

Both equations have the y value equal -2 when x = 3. Therefore, the overall solution is confirmed.

3 0
2 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

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3 years ago
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Answer:

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