Answer: Maybe it's the third one I'm not completely sure. don't take my word for it.
Step-by-step explanation:
If you divide 8 by three and you'd get 26 but the 6 keep reapeting
Answer:
Step-by-step explanation:
Hope this helps you.
<em>Can</em><em> </em><em>I</em><em> </em><em>have</em><em> </em><em>the</em><em> </em><em>brainliest</em><em> </em><em>please</em><em>?</em>
Step 1
Anything divided by one gives itself.
\frac{1}{8}=-8\text{ and }\frac{-8}{1}=\frac{-12}{48}
8
1
=−8 and
1
−8
=
48
−12
Step 2
Convert -8−8 to fraction -\frac{64}{8}−
8
64
.
\frac{1}{8}=-\frac{64}{8}\text{ and }\frac{-8}{1}=\frac{-12}{48}
8
1
=−
8
64
and
1
−8
=
48
−12
Step 3
Compare \frac{1}{8}
8
1
and -\frac{64}{8}−
8
64
.
\text{false}\text{ and }\frac{-8}{1}=\frac{-12}{48}false and
1
−8
=
48
−12
Step 4
Anything divided by one gives itself.
\text{false}\text{ and }-8=\frac{-12}{48}false and −8=
48
−12
Step 5
Reduce the fraction \frac{-12}{48}
48
−12
to lowest terms by extracting and canceling out 1212.
\text{false}\text{ and }-8=-\frac{1}{4}false and −8=−
4
1
Step 6
Convert -8−8 to fraction -\frac{32}{4}−
4
32
.
\text{false}\text{ and }-\frac{32}{4}=-\frac{1}{4}false and −
4
32
=−
4
1
Step 7
Compare -\frac{32}{4}−
4
32
and -\frac{1}{4}−
4
1
.
\text{false}\text{ and }\text{false}false and false
Step 8
The conjunction of \text{false}false and \text{false}false is \text{false}false.
\text{false}false
Hint
Do the arithmetic.
Solution
\text{false}false
First, find the area of the circle using the formula A=pi r^2.
A=pi (2x+3)^2 = pi(4x^2 + 12x + 9)
Second, find the area of the rectangle inside by multiplying the polynomials.
(X+1)*(3x+2) = 3x^2 + 5x +2
Third, subtract the area of the rectangle from the area of the circle to find the area of the shaded region.
pi(4x^2 + 12x + 9) - 3x^2 + 5x +2 =area of shaded region
Or
(pi (2x+3)^2) - ((X+1)(3x+2)) = area of shaded region
