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krek1111 [17]
3 years ago
13

(04.01 LC)

Chemistry
1 answer:
Marysya12 [62]3 years ago
5 0

Answer:

Substance at the beginning of a reaction- reactant

Substance at the end of a reaction- product

Number placed before a compound in a chemical equation- stoichiometric coefficient

Explanation:

In a reaction equation, the species written on the left hand side of the equation are called the reactants.

The reactants combine to form the species on the right hand side of the reaction equation called products.

The stoichiometric coefficient is a number written before the formula of a compound in the reaction equation.

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Answer:

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Explanation:

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2 years ago
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Does an electric iron may have a lower wattage than a LED lightbulb
grin007 [14]

Answer:

Below:

Explanation:

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8 0
3 years ago
An ion of iron has an 26 protons, 30 neutrons, and 23 electrons. What are its atomic number, atomic mass, and net charge?
sleet_krkn [62]

Answer:

Atomic number 26,atomic mass 26+30=56 dalton and net charge is 3+

Explanation:

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  The total number proton and neutrons present in the nucleus of an atom or ion is termed as atomic mass.From that point of view the the atomic mass of iron ion is 26+30=56 dalton

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3 years ago
Write the chemical formula for disilicon hexabromide.
Rasek [7]

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5 0
3 years ago
Complete and balance the molecular equation, including the phases, for the reaction of aqueous potassium sulfate, k2so4, and aqu
Tju [1.3M]
The reaction between K₂SO₄(aq) and SrI₂(aq) produces KI(aq) and SrSO₄(s) as products. 

The reaction is 
K₂SO₄(aq) + SrI₂(aq) → KI(aq)+ SrSO₄(s) 

To balance the equation both side of the reaction should have same number of atoms in each element.

Right hand side of the reaction has 1 K, 1 I, 1 Sr, 1 S and 4 O atoms while 2 K, 2 I, 1 Sr,1 S and 4 O present in left hand side of the reaction. 
Hence, number of I atoms and number of K atoms are not balanced. 
To balance the K atoms we should add 2 before KI. Then I atoms will be 2 at the right hand side. 

Hence, the balanced reaction equation is
K₂SO₄(aq) + SrI₂(aq) → 2KI(aq)+ SrSO₄(s) 
3 0
3 years ago
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