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Vikki [24]
2 years ago
10

How many grams of hydrogen are in 46 g of CH40?​

Chemistry
2 answers:
Romashka [77]2 years ago
6 0

Answer:

5.8 grams of hydrogen

Explanation:

Your welcome

aleksklad [387]2 years ago
4 0

mass H =

\tt \dfrac{molar~mass~H}{molar~mass~CH_4O}\times mass~CH_4O\\\\\dfrac{4}{32}\times 46~g=5.75~g

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An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the righ
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Displacement is a vector quantity(quantity having magnitude as well direction). Adding numbers towards right of 0 and subtracting towards left of 0 you'll get, Displacement = + 3 - 4 + 6 = + 5 units. Hope this helps.
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2 years ago
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Which of the following reactions Shows a chemical change producing a gas? APEX
Nina [5.8K]

Answer:2CH_3OH(l)+3O_2(g)\rightarrow2CO_2(g)+4H_2O(l)

Explanation: A chemical change is a reaction in which chemical composition of the substance changes. Some bonds are broken and some new bonds are formed.

The reactants are written in terms of their chemical formula on the left hand side and the products are written in terms of their chemical formula on right hand side with a arrow in between. The chemical symbols are followed by their physical states such as (l) for liquid, (s) for solid, (g) for gas and (aq) for aqueous.

Thus the only reaction producing a gas is 2CH_3OH(l)+3O_2(g)\rightarrow2CO_2(g)+4H_2O(l)

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3 years ago
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Calculate the total number of days therapy available within a 300 ml bottle of ranitidine (as hydrochloride) 75 mg/5 ml. oral so
Lisa [10]

<u>Answer:</u> This therapy is available for 15 days.

<u>Explanation:</u>

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Oral solution dosage = 75 mg/5 mL

To calculate the volume of oral situation for single dose per, we use unitary method:

The volume required for 75 mg of solution is 5 mL

So, the volume required for 300 mg of solution will be = \frac{5mL}{75mg}\times 300mg=20mL

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To calculate the number of days, we divide the total volume of the bottle by the volume of dose taken per night, we get:

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3 years ago
A balloon filled with helium gas at 1.00 atm occupies 12.9 L. What volume would the balloon occupy in the upper atmosphere, at a
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Answer:

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For the problem:

P1= 1 atm, V1= 12,9 L

P2=0,19 atm, V2=?

Therefore:

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