What was the process that Marie curie used to turn 8 tons of rubble into 1/5 of a teaspoon of radium?

Chemistry

1 answer:

hjlf4 years ago

5 0

I don’t think I knoe

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Fernando places 50 mL of HCl in a 100 mL beaker and 50 mL of NaOH in a 100 mL beaker. he places them on a scale together and mea

olchik [2.2K]

Answer:

The correct options are:

B. The HCl is the solute.

D. The H₂O is the solvent.

E. This mixture conducts electricity.

Explanation:

For the preparation of the HCl solution, 10 mL of HCl and 40 mL of water were mixed.

The compound that is present in the solution in a smaller ratio is the solute and the other compount -present in higher ratio- is the solvent.

So, the solute is HCl and the solvent is water (H₂O). Furthermore, water is considered as an universal solvent (for most of the polar and ionic compounds). According to this, the following options are correct:

B. The HCl is the solute.

D. The H₂O is the solvent.

Then, a condition for a solution that is able to conduct electricity is the presence of ions in the solution. When HCl is dissolved in water, it dissociates in ions according to the following equilibrium:

HCl ⇔ H⁺ + Cl⁻

The ions H⁺ and Cl⁻ are electrically charged so the solution can conduct electricity. According to this, the following option is also correct:

E. This mixture conducts electricity.

7 0

3 years ago

Cell,neclus,genes,chromosomes,tissue,organ,organ system organism arrange in order?

egoroff_w [7]

The order in increasing is:

genes, chromosomes, cells, tissue, organ, system, organism

7 0

3 years ago

Balanced equation for the combination of magnesium and oxygen to form magnesium oxide

Digiron [165]

2Mg(s) + O2(g) --> 2MgO(s)

8 0

3 years ago

In a titration of 0.35 M HCl and 0.35 M NaOH, how much NaOH should be added to 45.0 ml of HCl to completely neutralize the acid?

Bezzdna [24]

It would be the same amount. So, 45 ml of NaOH is required to be added to the 45 ml of HCI to neutralize the acid fully. Here is a brief calculation:

Firstly, here is your formula: M(HCI) x V(HCI) = M(NaOh) x V(NaOH)
With the values put in: 0.35 x 45 = 0.35 x V(NaOH)
= 45 ml.
There is 45 ml of V(NaOH)

Let me know if you need anything else. :)

- Dotz

6 0

3 years ago

Now molecules: ____ molecules of H2 + ____ molecules of O2 → ____molecules of H2O

Valentin [98]

Answer:

4 H2 + 1 O2 = 2 H2O

6 0

4 years ago