41.083 atm is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation.
Explanation:
Data given for argon gas:
number of moles = 1 mole
volume = 0.5 L
Temperature = 19 degrees or 292.15 K
a= 1.345 (L2⋅atm)/mol2
b= 0.03219L/mol.
R = 0.0821
The real pressure equation given by Van der Waals equation:
P =( RT ÷ Vm-b) - a ÷ Vm^2
Putting the values in the equation:
P = (0.0821 x 292.15) ÷(0.5 - 0.03219) - 1.345÷ (0.5)^2
= 23.98÷0.4678 - 1.345 ÷0 .25
= 51.26 - 5.38
= 45.88 atm is the real pressure.
The pressure from the ideal gas law
PV =nRT
P =( 1 x 0.0821 x 292.15) ÷ 0.5
= 4.797 atm
the difference between the ideal pressure and real pressure is
Pressure by vander waal equation- Pressure by ideal gas law
45.88 - 4.797
= 41.083 atm.is the difference between the two.
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Answer:
c) more particles collide with the walls of the container
Explanation:
More moles means more particles. If the volume remains the same, the collisions of more particles with the container walls cause the pressure to increase.
HEY THERE!
THE ANSWER IS: the properties of an ideal gas are: An ideal gas consists of a large number of identical molecules. The volume occupied by the molecules themselves is negligible compared to the volume occupied by the gas. The molecules obey Newton's laws of motion, and they move in random motion.
CREDITS:<span>physics.bu.edu/~duffy/py105/Idealgas.htm</span>
