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nexus9112 [7]
4 years ago
13

The volume of a gas in a container varies inversely with the pressure on the gas. If a gas has a volume of 220 cubic inches unde

r a pressure of 17 pounds per square inch, what will be its volume if the pressure is increased to 19 pounds per square inch? (Round off your answer to the nearest cubic inch.)
Physics
1 answer:
Aloiza [94]4 years ago
7 0

Answer:

The final Volume of the gas in the cylinder  V_{2} = 196.84 in^{3}

Explanation:

Given that the volume of a gas in a container varies inversely with the pressure on the gas.

⇒ P ∝ \frac{1}{V}

⇒ P V = constant

\frac{V_{2} }{V_{1} } = \frac{P_{1} }{P_{2} }  --------- (1)

Given that P_{1} = 17 \frac{lb}{in^{2} }

P_{2} = 19 \frac{lb}{in^{2} }

V_{1} = 220 in^{3}

⇒ \frac{V_{2} }{220} = \frac{17}{19}

⇒ V_{2} = 196.84 in^{3}

The final Volume of the gas in the cylinder  V_{2} = 196.84 in^{3}

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Answer:

7. Net constant force down the ramp

Explanation:

After the car is released and starts moving up the ramp, the only force that is applied on the car is weight because of the gravity, we were told that the friction force is neglected. the force because of the weight is given by:

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as you can see those values won't change, so the force remains constant down the ramp.

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Meteoroids are small objects in space, usually made of rock or metal. These bodies often get close to a planet and fall through
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Answer:

1. A burning streak of light, called a Meteor.

2.The rocky bodies that survives the fall to the planet’s surface are Meteorites.

Explanation:

Let us see the difference between them.  

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4 0
4 years ago
Read 2 more answers
Describe the difference between weather and climate.
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4 0
3 years ago
An electron is located on a pinpoint having a diameter of 3.52 µm. What is the minimum uncertainty in the speed of the electron?
Komok [63]

Explanation:

It is given that,

An electron is located on a pinpoint having a diameter of 3.52 µm, \Delta x=3.52\times 10^{-6}\ m

We need to find the minimum uncertainty in the speed of the electron. It can be calculated using Heisenberg uncertainty principal as :

\Delta p.\Delta x \geq \dfrac{h}{4\pi}

\Delta p \geq \dfrac{h}{4\pi \Delta x}

Since, p = m v

So, mv \geq \dfrac{h}{4\pi \Delta x}

\Delta v \geq \dfrac{h}{4\pi \Delta x m}

\Delta v \geq \dfrac{6.67\times 10^{-34}}{4\pi 3.52\times 10^{-6}\times 9.1\times 10^{-31}}

\Delta v\geq 16.57\ m/s

So, the minimum uncertainty in the speed of the electron is greater than 16.57 m/s. Hence, this is the required solution.

5 0
3 years ago
A 64.0 kg pole vaulter running at 10.2 m/s vaults over the bar. If the vaulter's horizontal component of velocity over the bar i
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Answer:

h = 5.05 m

Explanation:

given,

mass of pole vaulter, m = 64 Kg

speed of the vaulter,V = 10.2 m/s

horizontal component of velocity in air, v = 1 m/s

height of the jump,h = ?

using energy conservation

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\dfrac{1}{2}mv_i^2 + m g h_i= \dfrac{1}{2}mv_f^2+m g h_f

initial height of the vaulter is equal to zero.

\dfrac{1}{2}v_i^2 = \dfrac{1}{2}v_f^2+gh_f

h =\dfrac{v_i^2-v_f^2}{2g}

h =\dfrac{10^2-1^2}{2\times 9.8}

 h = 5.05 m

height of the jump is equal to 5.05 m.

4 0
4 years ago
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