1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Masja [62]
3 years ago
15

A toy car is given a quick push so that it moves up an inclined ramp. After it is released, it moves up, reaches its highest poi

nt and moves back down again. Friction is so small it can be ignored. What net force acts on the car?
1. Net constant force up the ramp
2. Net decreasing force down the ramp
3. Net force of zero
4. Net decreasing force up the ramp
5. Net increasing force up the ramp
6. Net increasing force down the ramp
7. Net constant force down the ramp
Physics
1 answer:
Alexeev081 [22]3 years ago
4 0

Answer:

7. Net constant force down the ramp

Explanation:

After the car is released and starts moving up the ramp, the only force that is applied on the car is weight because of the gravity, we were told that the friction force is neglected. the force because of the weight is given by:

F=m*g*sin(\theta)

where θ is the angle of the ramp.

as you can see those values won't change, so the force remains constant down the ramp.

You might be interested in
On august 10, 1972, a large meteorite skipped across the atmosphere above the western united states and western canada, much lik
RUDIKE [14]
(a)
The velocity of the meteorite just before hitting the ground is:
v=20 km/s=20000 m/s
The loss of energy of the meteorite corresponds to the kinetic energy the meteorite had just before hitting the ground, so:
\Delta K =  \frac{1}{2}mv^2= \frac{1}{2}(3.4 \cdot 10^6 kg)(20000 m/s)^2=6.8 \cdot 10^{14}J

(b) 1 megaton of tnt is equal to 1 MT=4.2 \cdot 10^{15}J
To find to how many megatons the meteorite energy loss \Delta E
corresponds, we can set the following proportion
1 MT: 4.2 \cdot 10^{15}J=x: \Delta E
And so we find
x=  \frac{\Delta E}{4.2 \cdot 10^{15}J}  = \frac{6.8 \cdot 10^{14}J }{4.2 \cdot 10^{15}J} =0.162 MT
So, 0.162 megatons.

(c) 1 Hiroshima bomb is equivalent to 13 kilotons (13 kT). The impact of the meteorite had an energy of \Delta E=0.162 MT=162 kT. So, to find to how many hiroshima bombs it corresponds, we can set the following proportion:
1:13 kT=x:162 kT
And so we find
x= \frac{162 kT}{13 kT}=12.46
So, the energy released by the impact of the meteorite corresponds to the energy of 12.46 hiroshima bombs.
7 0
4 years ago
The efficiency of a machine is always less than 100% because part of the energy input is used to
Travka [436]

Answer:

C. Overcome Friction

Explanation:

When using any machine usually those with moving parts, you may notice heat forming near the areas where most movement occurs. As friction continues, more energy is used up and released as heat. For that reason, the efficiency of a machine will forever be less than 100%

5 0
3 years ago
A 0.3 g mosquito is flying toward a girl with a speed of 4.5 mph. Just before landing on the girl, the fly is swatted straight b
luda_lava [24]

Answer:

1.1x10^-2N

Explanation:

We have the change in momentum as

P = 0.3(4.5+12)g.mph

= 0.3x0.447x(4.5+12)x10^-3

Then the force that is exerted will be

F = p/∆t

∆t = 0.2

= 0.3x0.447x(4.5+12)x10^-3/0.2

= 0.1341x16.5x10^-3/0.2

= 1.1x10^-2

Therefore the force that was exerted is equal to 1.1x10^-2

5 0
3 years ago
A football is kicked into the air with a velocity of 32m/s at an angle of 25º. At the very top of the ball’s path, its vertical
Lelu [443]

Answer:

Zero

Explanation:

The motion of the ball is the motion of a projectile, and it consists of two independent motions:

- A horizontal motion with constant velocity

- A vertical motion with constant acceleration g =9.8 m/s^2 towards the ground

We are only interested in the vertical component of the velocity, which is given by

v_y = v_0 sin \theta -gt

where

v0 = 32 m/s is the initial speed

\theta=25^{\circ} is the initial direction

t is the time

The vertical component of the velocity decreases until the ball reaches its maximum height. At that moment, the vertical velocity becomes zero, and then it changes direction (pointing downward).

3 0
4 years ago
If a simple machine reduces the strength of a force, what must be increased?. . A. the distance that the force move. . B. the wo
Karolina [17]
"The distance that the force moves" is the one among the following choices given in the question that must be increased, if <span>a simple machine reduces the strength of a force. The correct option among all the options that are given in the question is the first option or option "A". I hope the answer helped you.</span>
3 0
3 years ago
Read 2 more answers
Other questions:
  • Compared to yellow light, orange light has A. a shorter wavelength. B. a wavelength closer to that of gamma rays. C. the same fr
    13·1 answer
  • How much money did congress authorize to be spent on its construction
    13·1 answer
  • A highway patrolman traveling at the speed limit is passed by a car going 20 mph faster than the speed limit. After one minute,
    13·2 answers
  • 1. Someone fires a 0.04 kg bullet at a block of wood that has a mass of 0.5 kg. (The block of wood is sitting on a frictionless
    11·2 answers
  • Newton's second law is a major part of mechanics. However, it does have its limitations. Under what condition does the second la
    10·1 answer
  • If a galaxy is located 200 million light years from Earth, what can you conclude about the light from that galaxy?
    9·2 answers
  • Can anyone help me? (physics)
    12·1 answer
  • An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary
    11·1 answer
  • A makeshift sign hangs by a wire that is extended over an ideal pulley and is wrapped around a large potted plant on the
    8·1 answer
  • Which list places different units of matter in the correct sequence from smaller to largest
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!