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marissa [1.9K]
3 years ago
15

What is the speed of a vehicle that travels 80 meters in 2 seconds?

Physics
1 answer:
Firdavs [7]3 years ago
8 0

the formula for velocity is:

v= distance/time

distance= 80m

time=2 seconds

v=80/2

v=40ms-1

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A satellite in earth orbit has a mass of 99 kg and is at an altitude of 2.02 106 m. (assume that u = 0 as r â â.) (a) what is th
Ierofanga [76]

(a)          What is the potential energy: PE = -G * M * m/r

 

Where: M is the mass of the earth which is 5.98 * 10^24 kg.

m is the mass of the satellite.

r is the space from the center of the earth to the satellite

 

To conclude this distance add the radius of the earth to the altitude. Radius of the earth is 6.38 * 10^6 meters.

 

 

r = 6.38 * 10^6 + 2.02 * 10^6 = 8.38 * 10^6

PE = 6.67 * 10^-11 * 5.98 * 10^24 * 99/8.38 * 10^6 = 4.71240095 * 10^9 J

 

 

(b) magnitude of the gravitational force exerted by the Earth

 

Fg = G * M * m/r^2

Fg = 6.67 * 10^-11 * 5.98 * 10^24 * 99/(8.38 * 10^6)^2 = 562.3078873 N

 

 

(c) There are no other forces that the satellite exert on the Earth. So therefore, it is 0.

8 0
3 years ago
A certain electric circuit obeys Ohm's law. If the resistance of the circuit is doubled, what will happen to the current through
netineya [11]

Answer:

currrent will be halved

Explanation:

v = ir

v/r = i      multiply both sides by  1/ 2

v / (2r) = 1/2 i  

4 0
3 years ago
Katie practiced the fuute for 45 minutes then she ate a snack for 15 minutes. next,she watched television for 30 minutes,until 6
Akimi4 [234]
Started at 4.30 p.m ,15+45+30=1 hr 30 mins,6.00-1 hr 30 mins=4.30 p.m
6 0
4 years ago
A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 4.79 g coins stacked over the 28.8 cm mark, th
masha68 [24]

To solve the exercise, the key concept to be addressed is the Mass Center.

The center of mass of an object is measured as,

X_{cm} = \frac{\sum m_ix_i}{\sum m_i}

X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}

Our values are given by,

x_1 = 50cm

m_1 = ?

x_2 =28.8cm

m_2 = 4.79g

x_3 = 28.8cm

m_3 = 4.79g

X_{cm} = 38.4cm

Replacing the values in our previous equation we have,

X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}

38.4 = \frac{m_1(50)+2(28.8*4.79)}{m_1+2*4.79}

38.4(m_1+2*4.79)= m_1(50)+2(28.8*4.79)

38.4m_1 +367.872 = 50m_1+275.904

11.6m_1 = 91.968

m_1 = 7.928g

Therefore the mass of the meter stick is 7.928g

7 0
3 years ago
Sun *
Ludmilka [50]

Answer:

E

Explanation:

6 0
3 years ago
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