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DedPeter [7]
3 years ago
7

Solve for the BMI weight 58kg Height 1.61​

Physics
1 answer:
vaieri [72.5K]3 years ago
7 0

Answer:

Explanation:

BMI= weight/(height × height)          ; weight in kilogram and height in metter

     = 58kg / (1.61m  × 1.61m )

     = (58/ 2.5921) kg/m^{2}

     = 22.375  kg/m^{2}

     ≈ 22.4 kg/m^{2}

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Atoms are attracted to each other because____
yaroslaw [1]

Answer:

A

Explanation:

Opposite attract. Since electrons are negative they will be attracted to the protons because they a positive

4 0
3 years ago
What materials in a torch are conductors and insulators?
Alisiya [41]
Are you sure you weren't given any options? Basically the electrical components, e.g wires and bulbs will be conductors, and the part comprising the outer casing, e.g plastic, glass, will be insulators
8 0
4 years ago
Most of the Earth's volcanoes occur
timofeeve [1]

Answer:

A.

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NEAR THE CENTER OF TECTONIC PLATES.

3 0
3 years ago
La tension que se transmite en la cuerda BD es de 75 lb. Calcula el momento de fuerza generada por la cuerda respecto al punto C
Bas_tet [7]

Answer:

Mc = 1920[lb*in]

Explanation:

Para poder solucionar este problema debemos realizar un análisis estático, por tal motivo lo primero es realizar un diagrama de cuerpo libre con las respectivas fuerzas actuando sobre la barra ABC. DE igual manera calcular la geometría de la configuración mostrada.

El diagrama de cuerpo libre se puede ver en la imagen adjunta, con la solución de este problema.

Lo primero es determinar el angulo t, el cual por medio de las propiedades del triangulo rectángulo se puede determinar.

Con este angulo (t) ya determinado, fijamos la atención en el triangulo BCD, este triangulo no es rectángulo, pero por medio de la ley de senos podemos determinar el angulo omega.

Después de determinar el angulo omega, restamos el angulo (t) para poder determinar el angulo (a).

Seguidamente realizamos una sumatoria de momentos alrededor del punto C, utilizado las respectivas fuerzas con los ángulos descompuestos.

El momento en el punto C es de 1920 [Lb*in].

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7 0
3 years ago
4. A 1,000-kilogram satellite completes a uniform circular orbit of radius 8.0 x 10 meters as
lesantik [10]

Answer:

Zero

Explanation:

The work done by a force on an object is given by:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and the displacement of the object

In this situation, the force is the force of gravity acting on the satellite. This force always points towards the centre of the trajectory, so it is always perpendicular to the direction of motion of the satellite (since the orbit is circular), so \theta=90^{\circ} and cos \theta =0. Therefore, the work done by gravity is also zero.

5 0
3 years ago
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