How are the two types of glaciers similar and how are they different

1 answer:

7 0

They are similar as they both are made of compacted snow which recrystallizes into solid ice. they are different because one of them forms on high mountain valleys and are long and narrow and the other one covers much of a continent or a large island

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Electronic configuration of Ferrous sulphate

uranmaximum [27]

Answer:

It's no trouble

Explanation:

Electronic configuration of fe=1s2,2s2,2p6,3s2,3p6,4s2,3d6

e.c of fe3+=1s2,2s2, 2p6, 3s2, 3p6, 4s0, 3d5

e.c of S= 1s2,2s2, 2p6, 3s2, 3p4

e.c of s2-=1s2, 2s2, 2p6, 3s2, 3p6

Iron or Iron is the first element of the eighth group of the periodic table. This is the most attainable element in the womb and outside of the womb. This is the fourth most commonly found element in Earth's womb. It has four permanent isotopes, whose mass is 54, 56, 57 and 58.

[Ar] 3d6 4s2

5 0

3 years ago

Which diagram represents a physical change,only?

Lorico [155]

There is no diagram

8 0

3 years ago

Explain why you can not use a physical reaction to separate elements that are chemically bonded together

Rainbow [258]

Their atoms are too tightly bonded to each other for them to be separated by a physical reaction

3 0

3 years ago

An atom of selenium (Se) forms a monatomic ion. Which of the following ions does is most likely form?

Delvig [45]

Answer:

The correct answer is Se^2-

Explanation:

The elements of group VI-A are
O, S, Se and Te.
-2 is most likely form in groups VI-A elemenst like O^2- as well as S^2-. Similarly Se also have Se^2-.

Reason:

Actually these elements have 6 valence shell electrons and they want to get 2 more electrons in order to get nearest configuration of noble gases.

8 0

3 years ago

Read 2 more answers

For the following reactions, write a balanced equation using half-reactions and calculate the voltage to be expected.

Iteru [2.4K]

a) $2Na(s) +2H_2O(I)$ → $2Na^+(aq) + OH^-(aq)+ H_2(g)$

b) $2Ag (s) +2H^(aq)$ → $2 Ag^+ (aq) +H_2(g)$

<h3>What are half-reactions?</h3>

The half-reaction method is a way to balance redox reactions. It involves breaking the overall equation down into an oxidation part and a reduction part.

$2Na(s) +2H_2O(I)$ → $2Na^+(aq) + OH^-(aq)+ H_2(g)$

$E^0 cell = E^0 (reduction) - E^0 (oxidation)$