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3 years ago

A gas has a volume of 25.6 L at a temperature of 278 K. What will be the new temperature, in C, if

Chemistry

1 answer:

Inessa05 [86]3 years ago

7 0

<h2>Hello!</h2>

The answer is: -97.37° C

According to the Charles and Gay-Lussac's Law we have that:

$\frac{V}{T}=k$

Where:

<em>v</em> is the volume of the gas

<em>t</em> is the temperature of the gas

<em>k </em>is the proportionality constant

From the Gay-Lussac's Law we also have the following relation:

$\frac{V1}{T1}=\frac{V2}{T2}$

Since we need to find the new temperature (T2) we can use the last equation:

$\frac{V1}{T1}=\frac{V2}{T2}\\\\T2=\frac{V2*T1}{V1}=\frac{16.2L*278K}{25.6L}=175.92K$

We are asked to find the temperature in Celsius degrees, so, we must convert the result (in K) to Celsius degrees:

$Celsius=K-273.15=175.92-273.15=-97.37$

So, the temperature is -97.37° C

Have a nice day!

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jeka94

Answer:

$T_f$ = 25.05°C

Explanation:

Given:

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molar mass = 194.18g dimethylphthalate

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since we have our molar mass and mass of dimethylphthalate ;we can determine the number of moles as;

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21.84 kJ =6.15 kJ/°C $* (T_f-21,5^0C)$

21.84 KJ = $(6.15 kJ/^0C * T_f) - (6.15 kJ/^0C*21.5^0C)$

21.84 KJ = $(6.15 kJ/^0C * T_f)$ - 132.225 kJ

21.84 KJ + 132.225 kJ = $(6.15 kJ/^0C * T_f)$

154.065 kJ = $(6.15 kJ/^0C * T_f)$

$T_f$ = $\frac{154.065kJ}{6.15kJ/^0C}$

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