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inn [45]
3 years ago
14

A gas has a volume of 25.6 L at a temperature of 278 K. What will be the new temperature, in C, if

Chemistry
1 answer:
Inessa05 [86]3 years ago
7 0
<h2>Hello!</h2>

The answer is: -97.37° C

<h2>Why?</h2>

According to the Charles and Gay-Lussac's Law we have that:

\frac{V}{T}=k

Where:

<em>v</em> is the volume of the gas

<em>t</em> is the temperature of the gas

<em>k </em>is the proportionality constant

From the Gay-Lussac's Law we also have the following relation:

\frac{V1}{T1}=\frac{V2}{T2}

Since we need to find the new temperature (T2) we can use the last equation:

\frac{V1}{T1}=\frac{V2}{T2}\\\\T2=\frac{V2*T1}{V1}=\frac{16.2L*278K}{25.6L}=175.92K

We are asked to find the temperature in Celsius degrees, so, we must convert the result (in K) to Celsius degrees:

Celsius=K-273.15=175.92-273.15=-97.37

So, the temperature is -97.37° C

Have a nice day!

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