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eimsori [14]
3 years ago
12

An object undergoing simple harmonic motion has a maximum displacement of 6.2 m at t=0.0 s. if the angular frequency of oscillat

ion is 1.6 rad/s what is the objects displacement when t=3.5 s A) 3.1 m B) 5.6 m C) 4.8 m D) 3.7 m
Physics
1 answer:
Law Incorporation [45]3 years ago
4 0

Answer:

C

Explanation:

From above question we know that

A = 6.2 m

f = 1.6 rad/s

t = 3.5 s

x =?

We know that,

x = Acos(2pie ft)

Putting all values in above eq.

x = 6.2 x cos(2x3.142x1.6x3.5)

x = - 4.8

Displacement can never be negative so ignore - sign.

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Place the types of radiation in order of INCREASING mass.
lubasha [3.4K]

Answer & explanation:

  • Gamma Radiation (γ):  Also called gamma rays. Gamma radiation is made of electromagnetic waves, has zero charge and mass, continuously emits heat and has the ability to ionize air and make it conductive of electric current.
  • Beta radiation (β): Beta rays or beta particles, are electrons, negative particles with charge - 1 and mass number 0.
  • Alpha radiation (α): Also called alpha particles or alpha rays, are particles charged by two protons and two neutrons.  They have positive charge +2 and mass number 4.
5 0
4 years ago
) Force F = − + ( 8.00 N i 6.00 N j ) ( ) acts on a particle with position vector r = + (3.00 m i 4.00 m j ) ( ) . What are (a)
natali 33 [55]

To develop this problem it is necessary to apply the concepts related to the Cross Product of two vectors as well as to obtain the angle through the magnitude of the angles.

The vector product between the Force and the radius allows us to obtain the torque, in this way,

\tau = \vec{F} \times \vec{r}

\tau = (8i+6j)\times(-3i+4j)

\tau = (8*4)(i\times j)+(6*-3)(j\times i)

\tau = 32k +18k

\tau = 50 k

Therefore the torque on the particle about the origen is 50k

PART B) To find the angle between two vectors we apply the definition of the dot product based on the vector quantities, that is,

cos\theta = \frac{r\cdot F}{|\vec{r}|*|\vec{F}|}

cos\theta = \frac{(8*-3)+(4*3)}{\sqrt{(-3)^2+4^2}*\sqrt{8^2+6^2}}

cos\theta = -0.24

\theta = cos^{-1} (-0.24)

\theta = 103.88\°

Therefore the angle between the ratio and the force is 103.88°

5 0
3 years ago
the distance of a planet from its sun is 19000000 miles. if there are 29400000 seconds in one orbit, find the speed of the plane
lisabon 2012 [21]
Orbit circumference 
<span>= 2 pi *1.9*10^7 miles </span>

<span>time for orbit trip = 2.9*10^7 s </span>

<span>speed = 2 pi *1.9 / 2.9 miles/second </span>

<span>= 4.12 miles/second </span>

<span>You did not say what units </span>
<span>in miles per hour, multiply by 3600 and get </span>
<span>14,820 miles/hour</span>
8 0
4 years ago
What is the purpose of mucilage in the spaces around the cells of hornworts? Why is this important?
Bumek [7]

New Zealand hornworts and general information on them. ... in the top of the plant and remain attached to it and continue to grow throughout its life. ... are that the spaces between the cells are filled with mucilage rather then air chambers

7 0
3 years ago
A cardinal (Richmondena cardinalis) of mass 3.70×10−2 kg and a baseball of mass 0.144 kg have the same kinetic energy. What is t
Radda [10]

Answer:

\frac{p_{c}}{p_{b}}\approx 0.507

Explanation:

Since the cardinal and ball have the same kinetic energy, it is possible to determine the ratio between speeds. (c for cardinal, b for baseball)

K_{c} = K_{b}

\frac{1}{2}\cdot m_{c}\cdot v_{c}^{2}= \frac{1}{2}\cdot m_{b}\cdot v_{b}^{2}

\frac{v_{c}}{v_{b}}=\sqrt{\frac{m_{b}}{m_{c}} }

The ratio is obtained by multiplying each side by \frac{m_{c}}{m_{b}}:

\frac{p_{c}}{p_{b}}=\frac{m_{c}}{m_{b}}\cdot \sqrt{\frac{m_{b}}{m_{c}} }

\frac{p_{c}}{p_{b}}= \sqrt{\frac{m_{c}}{m_{b}} }

The value of this ratio is:

\frac{p_{c}}{p_{b}}\approx 0.507

3 0
4 years ago
Read 2 more answers
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