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ValentinkaMS [17]
3 years ago
9

If the net force acting on an object is 0 N the forces are

Physics
2 answers:
3241004551 [841]3 years ago
8 0

If the net force acting on an object is zero, then there <em>may be</em> no forces at all acting on it.  If there ARE any, then they're <em>balanced</em>.

elena-s [515]3 years ago
7 0

Its B) unbalanced because i have the same sentence on a quiz in Lesson 5: Friction and Gravity in science. So if its wrong im sorry i tried to help but if it is right then your welcome! :D

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The pressure in a section of horizontal pipe with a diameter of 2.5 cm is 139 kPa. Water ï¬ows through the pipe at 2.9 L/s. If t
My name is Ann [436]

Answer:

d = 2*0.87 = 1.75 cm

Explanation:

by using flow rate equation to determine the  speed in larger pipe

\phi =\pi r^2 v

v = \frac{\phi}{\pi r^2}

  = \frac{2900 cm^3/s}{3.14(1.25cm)^2}

= 591.10 cm/s

 = 5.91 m/s

by Bernoulli's EQUATION

p1 +\frac{1}{2} \rho v1^2 = p2 +\frac{1}{2} \rho v2^2

139000+ \frac{1}{2}*1000*5.91^2 = 101000 +\frac{1}{2}*1000* v2^2

solving for v2

v2 = 10.53 m/s

diameter can be determine by using flow rate equation

q = v \pi r^2

r^2 = \frac{q}{\pi v}

     = \frac{2900}{3.14*1053}

r = 0.87 cm

d = 2*0.87 = 1.75 cm

5 0
3 years ago
In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separatio
liubo4ka [24]

Answer:

The  value is  y  = 0.0025 \  m

Explanation:

From the question we are told that

   The  wavelength is  \lambda  =  500 \ nm

    The distance of separation is  d =  1\  mm  =  0.001 \ m

   The  distance from the screen is  D  =  5 \ m

Generally the separation between the adjacent bright fringe is mathematically represented as

       y  = \frac{D  *  \lambda }{ d}

=>    y  =  \frac{5 *  500 *10^{-9}}{0.001}

=>    y  = 0.0025 \  m

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3 years ago
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sashaice [31]
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4 0
3 years ago
Which would be most reliable source for information about the toxity of an industrial chemical
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6 0
3 years ago
Read 2 more answers
If an object is moving, then the magnitude of its ____ cannot be zero.
Bad White [126]
If an object is moving, then its speed and the magnitude
of its velocity aren't zero. 

If its velocity is constant (speed doesn't change and it's
moving in a straight line), then its acceleration is zero.

Looks like choice-D sums it up nicely.
7 0
3 years ago
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