Below are the choices:
a)0.2168 atm
<span>b)4.613 atm </span>
<span>c)34.60 atm </span>
<span>d467.4 atm
</span>
1 atm = 760mmHg : Therefore:
<span>3,506mmHg = 3,506/760 = 4.613 atm
</span>B is correct answer.
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Answer:
New temp = 135°C
Explanation:
From ideal gas equation
But; P1 = 10000Pa. P2 = 45000
V1 = 200 cc. V2 = 100 cc
T1 = 60°C. T2 = ??
From our formulae above
then T2= 45000×100×60÷ (10000×200)
T2= 135°C
Answer : The vapor pressure of the dry oxygen gas is, 736.2 torr
Explanation : Given,
Volume of sample of oxygen = 500 mL
Vapor pressure of oxygen + water = 760 torr
Vapor pressure of water = 23.8 torr
Now we have to determine the vapor pressure of the dry oxygen gas.
Vapor pressure of the dry oxygen gas = Vapor pressure of (oxygen + water) - Vapor pressure of water
Vapor pressure of the dry oxygen gas = 760 torr - 23.8 torr
Vapor pressure of the dry oxygen gas = 736.2 torr
Thus, the vapor pressure of the dry oxygen gas is, 736.2 torr
Answer:
C
Explanation:
okay, you need to look at the structures of the particles of matter in the solid, liquid and gas.
- particles in a solid are in fixed positions, where they can only vibrate in those positions ( take a look at ice, or rather, a brick)
- liquids have very small or rather, no spaces between them, but they can slide or rub against each other, like people in a <em>really tight</em> crowd I guess
- gas particles have very large spaces between them and they move randomly. these exibit what's called brownian motion.
- since water particles (and all other liquid particles) have negligible spacings and limited movement, that allows the dye particles to move from a region of high concentration to that of a low concentration. the aim for this is for the mixture/solution to reach an equilibrium, that is the mixture must get to a point where all regions have the same concentration of the dye.
you can refer to your coursebooks :)
correct where wrong please:)