1s²2s²2p⁶3s²3p⁵
Explanation:
In writing the first two electrons will go in the 1s orbital.
Since 1s can only hold two electrons the next 2 electrons for chlorine go in the 2s orbital.
The next six electrons will go in the 2p orbital.
The p orbital can hold up to six electrons.
We'll pull six in the 2p orbital and then put the next two electrons in the 3s.
Since the 3s is now full we'll move to the 3p where we'll place the remaining five electrons.
Hope this helped ;)
Depending on the testing process being used, it may affect the object by making it shape differently, scratch, it or sometimes do absolutely nothing. hope this helps:)
Answer: Option (a) is the correct answer.
Explanation:
The given data is as follows.
= 4.19 
= 1.9
Heat of vaporization (
) at 1 atm and 
is 2259 kJ/kg
= 0
Therefore, calculate the enthalpy of water vapor at 1 atm and as follows.
= +
= 0 + 2259 kJ/kg
= 2259 kJ/kg
As the desired temperature is given 
and effect of pressure is not considered. Hence, enthalpy of liquid water at 10 bar and is calculated as follows.
= 
= 334.781 kJ/kg
Hence, enthalpy of water vapor at 10 bar and is calculated as follows.
= 
= 2410.81 kJ/kg
Therefore, calculate the latent heat of vaporization at 10 bar and as follows.
= 
= 2410.81 kJ/kg - 334.781 kJ/kg
= 2076.029 kJ/kg
or, = 2076 kJ/kg
Thus, we can conclude that at 10 bar and latent heat of vaporization is 2076 kJ/kg.
Answer:
W = ΔKE = 1/2mv₂⁽²⁾ - 1/2mv₁⁽²⁾
Explanation:
Work means Change In Kinetic Energy.
Kinetic-Energy is equal to change in velocity multiplied by mass and divided by 2
∴ KE = 1/2m²
Change in Kinetic-Energy =KE₂ - KE₁
=1/2mv₂⁽²⁾ - 1/2mv₁⁽²⁾
The temperature of the gas.
