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Rzqust [24]
2 years ago
10

CH3-CH=CH3-CH what is the name of this structure? ​

Chemistry
1 answer:
Tasya [4]2 years ago
3 0

Answer:

if you meant CH3-CH=CH-CH3, the IUPAC name is 2-butene.

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The first step in the scientific methods is ask a question
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1 2 3 4 5 6 7 8 9 10 The diagrams show gases that are stored in two separate but similar containers. 2 identical containers have
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gas 2 because it has more particles colliding.

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The average lung capacity of a human is 6.0L.
Darya [45]

Answer:

(a) 0.25 mol

(b) 0.11 mol

(c) 8.77 mol

Explanation:

(a)

We use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 298 K

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

1.00 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\n=\frac{1.00\times 6.0}{0.0821\times 298}=0.25mol

(b)

We use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 0.296 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 200 K

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

0.296 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 200K\\\\n=\frac{0.296\times 6.0}{0.0821\times 200}=0.11mol

(c)

We use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 30 atm

V = Volume of the gas = 6.0 L

T = Temperature of the gas = 250 K

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

n = number of moles = ?

Putting values in above equation, we get:

30 atm\times 6.0L=n\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 250K\\\\n=\frac{30\times 6.0}{0.0821\times 250}=8.77mol

8 0
4 years ago
Calculate the ph of a solution having [OH-] = 8.2 x 10 ^-8M
egoroff_w [7]

Answer:

<h2>6.91 </h2>

Explanation:

To find the pH we must first find the pOH

The pOH can be found by using the formula

pOH = - log [ {OH}^{-} ]

We have

pOH =  -  log(8.2 \times  {10}^{ - 8} )  \\  = 7.086186...

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Next we use the equation

pH = 14 - pOH

We have

pH = 14 - 7.09

We have the final answer as

<h3>6.91</h3>

Hope this helps you

8 0
3 years ago
Use the data in the table above to calculate an approximate ΔH∘ in kilojoules for the synthesis of hydrazine from ammonia:
dmitriy555 [2]
On the left (reactant) side you have 6 N-H bonds and 1 Cl-Cl bond 
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7 0
3 years ago
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