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Explanation:
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Answer:
196000000 J
Explanation:
Potential Energy: This can be defined as the energy of a body due to its position in the gravitational field.
From the question,
P.E = mgh.................. Equation 1
Where P.E = potential Energy, m = mass of the water, h = height, g = acceleration due to gravity.
Given: m = 100 tonnes = (100×1000) = 100000 kg, h = 200 m
Constant: g = 9.8 m/s²
Substitute into equation 1
P.E = 100000(200)(9.8)
P.E = 196000000 J.
Note: When a object falls through a height he losses its potential energy.
Hence the potential energy lost = 196000000 J = 196 MJ.
Answer:
(2) the work required to move the electron is 4.8 x 10⁻¹⁹ J.
Explanation:
Given;
potential difference, V = 3.00 volts
charge of electron, q = 1.6 x 10⁻¹⁹ C
The work required to move an electron is calculated as;
W = Vq
where;
W is the work done in Joules
Substitute the given values and solve for W;
W = (3.00)(1.6 x 10⁻¹⁹)
W = 4.8 x 10⁻¹⁹ J.
Therefore, the work required to move the electron is 4.8 x 10⁻¹⁹ J.
A
. retaining gases around Earth to form the atmosphere ... gravity
B. stratifying the atmosphere into layers ... gravity
C. movements of tectonic plates ... gravity & buoyancy
D. spreading of the sea floor ... gravity & buoyancy
E. deflecting cosmic rays ... <em>Earth's magnetic field</em>
Answer:
I = 21.13 mA ≈ 21 mA
Explanation:
If
I₁ = 5 mA
L₁ = L₂ = L
V₁ = V₂ = V
ρ₁ = 1.68*10⁻⁸ Ohm-m
ρ₂ = 1.59*10⁻⁸ Ohm-m
D₁ = D
D₂ = 2D
S₁ = 0.25*π*D²
S₂ = 0.25*π*(2*D)² = π*D²
If we apply the equation
R = ρ*L / S
where (using Ohm's Law):
R = V / I
we have
V / I = ρ*L / S
If V and L are the same
V / L = ρ*I / S
then
(V / L)₁ = (V / L)₂ ⇒ ρ₁*I₁ / S₁ = ρ₂*I₂ / S₂
If
S₁ = 0.25*π*D² and
S₂ = 0.25*π*(2*D)² = π*D²
we have
ρ₁*I₁ / (0.25*π*D²) = ρ₂*I₂ / (π*D²)
⇒ I₂ = 4*ρ₁*I₁ / ρ₂
⇒ I₂ = 4*1.68*10⁻⁸ Ohm-m*5 mA / 1.59*10⁻⁸ Ohm-m
⇒ I₂ = 21.13 mA