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svlad2 [7]
3 years ago
15

A diffraction grating is illuminated simultaneously with red light of wavelength 670 nm and light of an unknown wavelength. The

fifth-order (m=5) maximum of the unknown wavelength exactly overlaps the third-order (m=3) maximum of red light.
What is the unknown wavelength?
Physics
1 answer:
bekas [8.4K]3 years ago
3 0

Answer:

402 nm .

Explanation:

Let the wave length of unknown light be λ .

For fifth order maxima the condition is

path difference at the point of fringe = 5 λ

For red light of 670 nm , for 3 rd order maxima

path difference at the point of fringe = 3  x wave length

= 3 x 670 nm

From these two equations

5 λ = 3 x 670 nm

λ = 3 x 670 / 5 nm

= 402 nm .

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A 29.0 kg beam is attached to a wall with a hi.nge while its far end is supported by a cable such that the beam is horizontal.
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The vertical component of force exerted by the hi.nge on the beam will be,142.10N.

To find the answer, we need to know more about the tension.

<h3>How to find the vertical component of the force exerted by the hi.nge on the beam?</h3>
  • Let's draw the free body diagram of the system.
  • To find the vertical component of the force exerted by the hi.nge on the beam, we have to balance the total vertical force to zero.

                      F_V+T sin\alpha -mg=0\\F_V=mg-Tsin\alpha \\

  • To find the answer, we have to find the tension,

                     Tlsin\alpha - mg\frac{l}{2}sin\beta =0\\ \\Tlsin\alpha = mg\frac{l}{2}sin\beta\\\\Tsin57=\frac{mg}{2}sin90\\\\T=\frac{mg}{2sin57} =169.43N

  • Thus, the vertical component of the force exerted by the hi.nge on the beam will be,

                F_V=(29*9.8)-(169.43*sin57)=142.10N

Thus, we can conclude that, the vertical component of force exerted by the hi.nge on the beam will be,142.10N.

Learn more about the tension here:

brainly.com/question/28106868

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Which of the following statements is true?
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Answer:

d.Energy as heat transferred into an object is determined by the amount of work done on the object.

Explanation:

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Describe how freezing could be used to remove sugar from a mixture of sugar and water?
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When the mixture (the sugar and water) is frozen, it separates. The water molecules get closer together, separating and pushing the sugar crystals to the top.<span />
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Problem 4: a long wire carries current towards east. a positive charge moves westward and just north from the wire. what is the
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The direction of the force experienced by the positive charge is upward.

We can use the right-hand rule to understand the direction of the Lorentz force acting on the charge: let's put the thumb in the same direction of the current in the wire (eastward), while the other fingers "wrap themselves" around the wire. These other fingers give the direction of the Lorentz force in every point of the space around the wire. Since the charge is located north of the wire, in that point the fingers are directed upward, so the positive charge experiences a force directed upward.
(if it was a negative charge, we should have taken the opposite direction)
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3 years ago
Canadian geese migrate essentially along a north-south direction for well over a thousand kilometers in some cases, traveling at
Wewaii [24]

Answer:

θ=19.877⁰

Explanation:

Given data

Velocity Va=34.0 km/h

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Sinθ=(Va/Vb)

Sinθ=(34.0/100)

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θ=19.877⁰

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