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coldgirl [10]
3 years ago
10

Please help !

Mathematics
1 answer:
garri49 [273]3 years ago
6 0

the answer for 1 is 3.6, 2 is 4/00, 3 is 1.367, and 4 is 4567937468436

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In right △ABC , the right angle is at C, m∠A=30∘ , and AC=5√ 5 units.
Makovka662 [10]

Answer:

5\sqrt{15}+5\sqrt{5}

Step-by-step explanation:

The core uses the value of the Pythagorean theorem and special angles.

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What is the written form of the fraction 1/3 ? Patty stirred 1/3 cup of milk into the macaroni and cheese. A. one-third B. one t
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One third is the written form.
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HigherOrder thing name two rays with the same endpoint in the figure below. Do they form an angle? Explain.
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where is the figure?

Step-by-step explanation:

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3 years ago
z varies jointly with x and y. When x = 2 and y = 3, z = 60. What is the value of z when x = 4 and y = 9?
kondor19780726 [428]
2 x 3 = 6 x 10 = 60
<em>Assuming that you are using the same rule:
</em><em>4 x 9 x 10 = 360
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6 0
3 years ago
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A cooler contains fifteen bottles of sports drink: eight lemon-lime flavored and seven orange flavored
dem82 [27]

Answer:

Mutually exclusive,

P(\text{Lemon-lime or orange})=\frac{2}{3}

Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the  probability.

A cooler contains twelve bottles of sports  drink: four lemon-lime flavored, four  orange flavored, and four fruit-punch  flavored. You randomly grab a bottle. It  is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}

P(\text{Lemon-lime})=\frac{4}{12}

P(\text{Lemon-lime})=\frac{1}{3}

Let us find probability of finding one orange drink.

P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}

P(\text{Orange})=\frac{4}{12}

P(\text{Orange})=\frac{1}{3}

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})

P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}

P(\text{Lemon-lime or orange})=\frac{1+1}{3}

P(\text{Lemon-lime or orange})=\frac{2}{3}

Therefore, the probability of choosing a lemon lime or orange is \frac{2}{3}.

8 0
3 years ago
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