It would be x to the 1/4. Just like how the square root of x is to the power 1/2. Its just something you have to remember that the root is the denominator and the power under the radical is the numerator
The true statements for this graph are:
B. The domain is the set of all real numbers.
D. The range is the set of all real numbers greater than or equal to zero.
<h3>What is a domain?</h3>
A domain can be defined as the set of all real numbers for which a particular function is defined. For this graph, the vertex of the parabola is (1, 0) and as such, the equation will be given by:
y = (x - h)² + k
y = (x - 2)² + 0
y = x² -4x + 4
Therefore, the graph's domain include a set of all real numbers.
<h3>What is a range?</h3>
A range refers to a set of all real numbers that connects with the elements of a domain. For this graph, we can observe that only real numbers greater than or equal to zero (0) are connected to the values on the x-axis of the domain.
In conclusion, we can logically deduce that the true statements for this graph are:
- Its domain include all real numbers.
- Its range include all real numbers that are greater than or equal to zero (0).
Read more on domain here: brainly.com/question/17003159
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Answer:
D. 2
Step-by-step explanation:
The degree is the biggest exponent. In this case, it is 2.
9514 1404 393
Answer:
(c) 162 cm
Step-by-step explanation:
The centroid divides a median into parts with the ratio 1:2, so RL:LD = 1:2. Then RL:RD = 1:(1+2), and RD = 3RL.
RD = 3·54 cm
RD = 162 cm
Answer:
a) First graph
The solution of the given inequalities -1 ≤ x ≤ 7
Step-by-step explanation
Given two inequalities
- 4 ≤ 3 x -1 ...(i)
2 x +4 ≤ 18 ...(ii)
From(i)
- 4 ≤ 3 x -1
Adding '1' on both sides , we get
- 4 + 1 ≤ 3 x - 1 +1
- 3 ≤ 3 x
Dividing '3' on both sides , we get
-1 ≤ x ...(a)
From (ii)
2 x +4 ≤ 18
subtracting '4' on both sides , we get
2 x + 4 - 4 ≤ 18 -4
2 x ≤ 14
dividing '2' on both sides, we get
x ≤ 7 ..(b)
Now the solution of two inequalities From(a) and (b)
-1 ≤ x ≤ 7
<u>Final answer</u>:-
The graph of the two inequalities is first graph