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Xelga [282]
3 years ago
12

How many times for the moon circle the Sun in a year

Physics
1 answer:
Juliette [100K]3 years ago
7 0

The Earth and the Moon circle their common center of mass, and
that common center of mass is what circles the Sun, once a year.


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A merchant in Katmandu sells you a solid gold 1.00-kg statue for a very reasonable price. When you get home, you wonder whether
White raven [17]

Answer:

a) 51.8 cm³

b) kg/m³ is a dimension of density (mass/volume). The regular unitys for volume are m³, cm³, L, gallons.

Explanation:

a) The density of pure gold is 19.3 g/cm³. When put in water, the piece of gold will occupy a volume, so that the volume of water will be displaced. To know the volume, we must divide the mass for the density (mass must be in grams because of the units of the density)

V = 1000/19.3

V = 51.8 cm³

7 0
3 years ago
How is soil different from crushed rock?
ira [324]
D. Soil is composed of weathered parent material where as crushed rock is not.
3 0
3 years ago
Which of the following are advantages of the SI system?
saul85 [17]

Answer:

A is the answer

Explanation:

That's why it ranges from big to small.

6 0
3 years ago
Read 2 more answers
A 1.25 kg block is attached to a spring with spring constant 17.0 N/m . While the block is sitting at rest, a student hits it wi
Free_Kalibri [48]

Answer:

The amplitude of the subsequent oscillations is 13.3 cm

Explanation:

Given;

mass of the block, m = 1.25 kg

spring constant, k = 17 N/m

speed of the block, v = 49 cm/s = 0.49 m/s

To determine the amplitude of the oscillation.

Apply the principle of conservation of energy;

maximum kinetic energy of the stone when hit = maximum potential energy of spring when displaced

K.E_{max} = U_{max}\\\\\frac{1}{2} mv^2 = \frac{1}{2} kA^2\\\\where;\\\\A \ is \ the \ maximum \ displacement = amplitude \\\\mv^2 = kA^2\\\\A^2 = \frac{mv^2}{k} \\\\A = \sqrt{\frac{mv^2}{k}} \\\\A =  \sqrt{\frac{1.25\  \times \ 0.49^2}{17}} \\\\A = 0.133 \ m\\\\A = 13.3 \ cm

Therefore, the amplitude of the subsequent oscillations is 13.3 cm

6 0
3 years ago
An 5-kg animal accelerates from rest to 10 m/s in 10 m and encounters an average drag force of 12 N. What is the average power o
MArishka [77]

Answer:

60 watts

Explanation:

Given that

Mass of the animal, m = 5 kg

Velocity of the animal, v = 10 m/s

Distance moved by the animal, d = 10 m

Drag force, F(d) = 12 N

Time taken, t = 2 seconds

To start with, we need to find the power output in itself before proceeding to find the average power output. And as such, we have

Power = Force * Distance/Time

But Distance/Time is velocity, so

Power = Force * Velocity

Power = 12 * 10

Power = 120 W.

We then use this power gotten to find the average power output.

Power(avg) = P/t

Power(avg) = 120 / 2

Power(avg) = 60 Watts.

Therefore, the average power output is found to be 60 Watts

5 0
3 years ago
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