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3 years ago

10

An astronaut is taking a space walk near the shuttle when her safety tether breaks. what should the astronaut do to get back to

the shuttle?

1 answer:

GuDViN [60]3 years ago

7 0

get hold of some of her equipment, and throw it away from the craft. she should recoil to the craft ... and hope ???

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How to find direction of magnetic field.

Tju [1.3M]

unlock your third eye and youll be able to see it

6 0

2 years ago

Find the change in velocity of a 369 g hockey puck subject to the force shown below.

Elena-2011 [213]

Answer:

The change in velocity is 15.83 [m/s]

Explanation:

Using the Newton's second law we have:

ΣF = m*a

The force in the graph is 185 N, therefore:

$185=0.369*a\\Where\\a=acceleration made it by the force [m/s^2]$

$a=501.35[m/s^2]$

Now using the following kinematic equation:

$V^{2}=Vi^{2} + 2*a*(x-xi) \\where\\V=final velocity [m/s]\\Vi= initial velocity [m/s] = 0 the hockey disk is in rest when receives the hit.\\ x = Final position [m] = 0.4 m\\xi = initial position [m] = 0.15m\\$

Now replacing the values:

$V^{2}=0 + 2*501.35*(0.4-0.15)\\ \\V= 15.83[m/s]$

3 0

3 years ago

Three small balls of the same size but different masses are hung side-by-side in parallel on the strings of same length. They to

andrey2020 [161]

Answer:

m1/6 ( c )

Explanation:

since all the balls starts having the same momentum after the two collisions we will apply the principal of conservation of energy

After first collision

m1v = m1v1 + m2v2 --- ( 1 )

After second collision

m2v2 = m2v2 + m3v3 ---- ( 2 )

combining equations 1 and 2

m1v = m1v1 + m2v2 + m3v3 ----- ( 3 )

All balls moving at the same momentum ( p ) = m1v1 = m2v2 = m3v3

note ; 3p = m1v ∴ m3 = $\frac{m1v}{3v3}$ ----- ( 4 )

applying conservation of energy

3v = v1 + v2 + v3 ------- ( 5 )

also 3m1v1 = m1v = v1 = v/3 =

v2 + v3 = 8/3 v ----- ( 6 )

next eliminate V3 for equation 6 by applying conservation of energy and momentum

m1 = 2m2 ------ ( 7 )

now using p1 = p2 = m1v1 = 1/2 m1v1 hence v2 = 2v1 where v1 = 1/3 v

hence ; v2 = 2/3 v ------- ( 8 )

solving with equation 6 and 8

v3 = 2v ------ ( 9 ) ∴ v/v3 = 1/2 ---- ( 10 )

solving with equation 9 and 10

m3 = m1/3 * 1/2 = m1/6

8 0

3 years ago

Calculate the average speed of a snake that moves 700 meters in 5 hours?

ddd [48]

140 ? i’m guessing there doesn’t look like there’s much to the question

7 0

3 years ago

Read 2 more answers

A pressurized tank of water has a 10-cm-diameter orifice at the bottom, where water discharges to the atmosphere. The water leve

Alex Ar [27]

Answer:

The velocity is 18.68m/s

Explanation:

Bernoulli's equation is applicable for stream line flow of a fluid. The flow must be steady and uniform flow. The Bernoulli's equation between inlet and outlet is written as:

P1/pg + V1/2g + Z1 = P2/pg + V2^2 + Z2

Where V1 and V2 are velocity of fluid at point 1 and 2b. The diameter of the tank too will be larger than that of the nozzle. Hence the velocity at point 1 will be 0.V1= 0

Substituting the values in to the equation

250 ×10^3/1000g + 0/g + 2.5 = 100×10^3/1000g + V2^2/2g + 0

250 + 2.5g = 100 + V2^2/2

250 + (2.5 × 9.8) = 100 V2^2/2

250 + 23.525- 100 = V2^2/2

174.525 = V2^2/2

Cross multiply

174.525 × 2 = V2^2

V2 = 349.05

V2 = Sqrt(349.05)

V2 = 18.68m/s

6 0

3 years ago

Read 2 more answers