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PtichkaEL [24]
3 years ago
9

This is a temperature where the vapor pressure of a liquid equals the atmospheric pressure.

Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Answer:

The answer is boiling point.

Explanation:

The boiling point of a substance refers to the temperature at which the vapour pressure of a liquid equals the atmospheric pressure; at this point the liquid will boil. Different liquids have different boiling points that are unique to them. This makes it possible for scientists to use boiling points as one of the criteria by which a liquid substance can be identified. At boiling point, the chemical bonds that are holding liquid particles together are destroyed and the liquid turn to gas.

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the radius of magnesium atom is 0.160nm. the radius of a magnesium ion is 7.2x 10^-11m. explain the difference in size between t
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Answer:

during reaction magnesium lises ions.

Explanation:

magnesium reacts by losing two ions which makes it smaller in size.

8 0
3 years ago
Which elements are not likely to bond with other elements? and why
noname [10]

Answer:

Helium, Neon, Argon, Krypton, Xenon, Radon, and Oganesson

Explanation:

they have full outer shells

8 0
2 years ago
QUESTION 8: When would acceleration increase most? *
sergey [27]

Answer:

Rolling down a steep hill

Explanation:

5 0
3 years ago
Balance the following equations:C(s) +CO2(g)- CO(g)
Nutka1998 [239]

Answer:

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6 0
3 years ago
Which numerical setup can be used to calculate the<br> atomic mass of the element bromine?
Gekata [30.6K]

Answer:

From the numerical steps highlighted under explanation, the average atomic mass of bromine is 79.91 u

Explanation:

The steps to be taken will involve;

1) Find the number of isotopes of bromine.

2) Identify the atomic mass and relative abundance of each of the isotopes.

3) Multiply the atomic mass of each of the isotopes by their corresponding values relative abundance value.

4) Add the value in step 3 above to get the average atomic mass of bromine.

Now;

Bromine has 2 isotopes namely;

Isotope 1: Atomic mass = 78.92amu and a relative abundance of 50.69%.

Isotope 2: Atomic mass = 80.92amu and a relative abundance of 49.31%.

Using step 3 above, we have;

(78.92 × 50.69%)

And (80.92 × 49.31%)

Using step 4 above, we have;

(78.92 × 50.69%) + (80.92 × 49.31%) ≈ 79.91 u

6 0
3 years ago
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