Question

The concentration in (M) of bromide ions ina

Answer 1

Answer : The concentration in (M)of bromide ions in a saturated solution of mercury (II) bromide is, $2.7\times 10^{-7}M$

Explanation :

The solubility equilibrium reaction will be:

$HgBr_2\rightleftharpoons Hg^{2+}+2Br^{-}$

Let the molar solubility be 's'.

The expression for solubility constant for this reaction will be,

$K_{sp}=[Hg^{2+}][Br^{-}]^2$

$K_{sp}=(s)\times (2s)^2$

$K_{sp}=4s^3$

Given:

$K_{sp}$ = $8.0\times 10^{-20}$

Now put all the given values in the above expression, we get:

$K_{sp}=4s^3$

$8.0\times 10^{-20}=4s^3$

$s=2.7\times 10^{-7}M$

Therefore, the concentration in (M)of bromide ions in a saturated solution of mercury (II) bromide is, $2.7\times 10^{-7}M$