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Andrew [12]
2 years ago
7

Two descriptions for a sub-atomic particle are listed below:

Chemistry
2 answers:
zhenek [66]2 years ago
5 0

C) Electrons and neutrons :)

Good luck!:)

Please Mark me Brainliest :)

:)

Dmitrij [34]2 years ago
4 0
Can not be D or B and A is not enough so C is right.
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3 years ago
An electrochemical cell is composed of pure nickel and pure iron electrodes immersed in solutions of their divalent ions at room
Andrej [43]

Answer:

0.758 V.

Explanation:

Hello!

In this case, case when we include the effect of concentration on an electrochemical cell, we need to consider the Nerst equation at 25 °C:

E=E\°-\frac{0.0591}{n} log(Q)

Whereas n stands for the number of moles of transferred electrons and Q the reaction quotient relating the concentration of the oxidized species over the concentration of the reduced species. In such a way, we can write the undergoing half-reactions in the cell, considering the iron's one is reversed because it has the most positive standard potential so it tends to reduction:

Fe^{2+}+2e^-\rightarrow Fe^0\ \ \ E\°=0.440V\\\\Ni^0\rightarrow Ni^{2+}+2e^-\ \ \ E\°=-0.250V

It means that the concentration of the oxidized species is 0.002 M (that of nickel), that of the reduced species is 0.40 M and there are two moles of transferred electrons; therefore, the generated potential turns out:

E=(0.440V+0.250V)-\frac{0.0591}{2} log(\frac{0.002M}{0.40M} )\\\\E=0.758V

Beat regards!

8 0
3 years ago
Briefly discuss the 3 most important properties of metals
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Conductivity: Metals are excellent conductors of electricity and heat.

Explanation: Hope this helped!

7 0
2 years ago
Write the complete balanced equation for the reaction between aluminum metal (Al) and oxygen gas (O2). You do not need to make t
Soloha48 [4]
For the answer to the question above, asking to w<span>rite the complete balanced equation for the reaction between aluminum metal (Al) and oxygen gas (O2)and You do not need to make the subscripts smaller.
My answer would be,
</span><span>4Al(s) + 3O2(g) --->2 Al2O3(s)
</span>
I hope this helps.
3 0
3 years ago
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