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3 years ago

The first stable compound produced from co2 in the light-independent reaction is

Chemistry

1 answer:

Andre45 [30]3 years ago

6 0

The first stable compound produced from the CO2 in the light independent reaction is PG.

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Match each SI unit to the quantity it measures mass temperature time electric current

kherson [118]

The S.I unit for the given term:

Mass is expressed in kilogram (kg)

temperature is expressed in kelvin (K)

Time is expressed in seconds (s)

Current is expressed in ampere (A)

Explanation:

Current:

The current can be defined as the electric charge flow in the surface (means ratio of charge per unit time). It is measured in ampere (A)

$Current\ I=\frac{\text { charge }}{\text { time }}$

Temperature: 

Kelvin (K), the general temperature unit in the international standard units system. The Kelvin scale is an absolute thermodynamic temperature scale that uses absolute zero, a temperature at which all thermal movements end with a classic description of thermodynamics.

Mass: 

Mass is both a feature of the objects weight and its resistance measurement to accelerate under the influence of pure force. The mass of the object also determines the gravitational force. The basic unit of mass is kilogram (kg)

Time: 

Time is the measurement of how much distance the objects takes to travel from one to another (speed). It is expressed in seconds (s).

5 0

3 years ago

A sample of a monoprotic acid (ha) weighing 0.384 g is dissolved in water and the solution is titrated with aqueous naoh. if 30.

posledela

The formula for the monoprotic acid is taken as HA, reaction with base is as follows;
HA + NaOH ---> NaA + H₂O
Stoichiometry of acid to base is 1:1
At the neutralisation point, number of HA moles = number of base moles
Number of NaOH moles reacted = 0.100M / 1000 mL /L x 30.0 mL = 0.003 mol
Therefore number of HA moles reacted = 0.003 mol
the mass of acid 0.384 g
Therefore molar mass - 0.384 g/ 0.003 mol = 128 g/mol

3 0

3 years ago

Answer A B C and D please for my chemistry hw

r-ruslan [8.4K]

Answer: The equations are provided below.

Explanation:

Skeleton equations are defined as the equations which simply indicate the molecules that are involved in a chemical reaction. These equations are unbalanced equations.

Balanced equations are defined as the chemical equation in which number of individual atoms on the reactant side must be equal to the number of individual atoms on the product side.

For A:

Water decomposes in the direct current to form hydrogen and oxygen.

Skeleton Equation: $H_2O(l)\rightarrow H_2(g)+O_2(g)$

Balanced Equation: $2H_2O(l)\rightarrow 2H_2(g)+O_2(g)$

For B:

Mercury (II) oxide decomposes in heat to form mercury, oxygen.

Skeleton Equation: $HgO(s)\rightarrow Hg+O_2$

Balanced Equation: $2HgO(s)\rightarrow 2Hg+O_2$

For C:

Calcium carbonate when heated forms calcium oxide and carbon dioxide.

Skeleton Equation: $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

Balanced Equation: $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

For D:

Group 2 hydroxides, when heated forms oxide and water vapor.

Skeleton Equation: $Ca(OH)_2\rightarrow CaO+H_2O$

Balanced Equation: $Ca(OH)_2\rightarrow CaO+H_2O$

3 0

3 years ago

The solubility of KCl is 3.7 M at 20 °C. Two beakers each contain 100. mL of saturated KCl solution: 100. mL of 4.0 M HCl is add

JulijaS [17]

Answer:

a)The Ksp was found to be equal to 13.69

Explanation:

Terminology

Qsp of a dissolving ionic solid — is the solubility product of the concentration of ions in solution.

Ksp however, is the solubility product of the concentration of ions in solution at EQUILIBRIUM with the dissolving ionic solid.

Note that if Qsp > Ksp , the solid at a certain temperature, will precipitate and form solid. That means the equilibrium will shift to the left in order to attain or reach equilibrium (Ksp).

Step-by-step solution:

To solve this:

#./ Substitute the molar solubility of KCl as given into the ion-product equation to find the Ksp of KCl.

#./ Find the total concentration of ionic chloride in each beaker after the addition of HCl. We pay attention to the amount moles present at the beginning and the moles added.

#./ Find the Qsp value to to know if Ksp is exceeded. If Qsp < Ksp, nothing will precipitate.

a) The equation of solubility equilibrium for KCL is thus;

KCL_(s) ---> K+(aq) + Cl- (aq)

The solubility of KCl given is 3.7 M.

Ksp= [K+][Cl-] = (3.7)(3.7) =13.69

The Ksp was found to be equal to 14.

In pure water KCl

Ksp =13.69 KCl =[K+][Cl-]

Let x= molar solubility [K+],/[Cl-] :. × , x

Ksp =13.69 = [K+][Cl-] = (x)(x) = x²

x= √ 13.69 = 3.7 M moles of KCl requires to make 100mL saturated solutio

37M moles/L

The Ksp was found to be equal to 14.

4.0 M HCl = KCl =[K+][Cl-]

Let y= molar solubility :. y, y+4

Ksp =13.69= [K+][Cl-] = (y)(y*+4)

* - rule of thumb

Ksp =13.69= [K+][Cl-] = (y)(y*+4)= y(4)

13.69=4y:. y= 3.42 moles/100mL

y= 34.2moles/L

8 M HCl = KCl =[K+][Cl-]

Let b= molar solubility :. B, b+8

Ksp =13.69= [K+][Cl-] = (b)(b*+8)

* - rule of thumb

Ksp =13.69= [K+][Cl-] = (b)(b*+8)= b(8)

13.69=8b:. b= 1.71 moles/100mL

17.1 moles/L

Therefore in a solution with a common ion, the solubility of the compound reduces dramatically.

8 0

3 years ago

Read 2 more answers

For the reaction A +B+ C D E, the initial reaction rate was measured for various initial concentrations of reactants. The follow

lora16 [44]

Answer:

Rate constant of the reaction is $3.3\times 10^{-3} M^{-2} s^{-1}$ .

Explanation:

A + B + C → D + E

Let the balanced reaction be ;

aA + bB + cC → dD + eE

Expression of rate law of the reaction will be written as:

$R=k[A]^a[B]^b[C]^c$

Rate(R) of the reaction in trail 1 ,when :

$[A]=0.30 M,[B]=0.30 M,[C]=0.30 M$

$R=9.0\times 10^{-5} M/s$

$9.0\times 10^{-5} M/s=k[0.30 M]^a[0.30 M]^b[0.30 M]^c$ ...[1]

Rate(R) of the reaction in trail 2 ,when :

$[A]=0.30 M,[B]=0.30 M,[C]=0.90 M$

$R=2.7\times 10^{-4} M/s$

$2.7\times 10^{-4} M/s=k[0.30 M]^a[0.30 M]^b[0.90 M]^c$ ...[2]

Rate(R) of the reaction in trail 3 ,when :

$[A]=0.60 M,[B]=0.30 M,[C]=0.30 M$

$R=3.6\times 10^{-4} M/s$

$3.6\times 10^{-4} M/s=k[0.60 M]^a[0.30 M]^b[0.30 M]^c$ ...[3]

Rate(R) of the reaction in trail 4 ,when :

$[A]=0.60 M,[B]=0.60 M,[C]=0.30 M$

$R=3.6\times 10^{-4} M/s$

$3.6\times 10^{-4} M/s=k[0.60 M]^a[0.60 M]^b[0.30 M]^c$ ...[4]

By [1] ÷ [2], we get value of c ;

c = 1

By [3] ÷ [4], we get value of b ;

b = 0

By [2] ÷ [3], we get value of a ;

a = 2

Rate law of reaction is :

$R=k[A]^2[B]^0[C]^1$

Rate constant of the reaction = k

$9.0\times 10^{-5} M/s=k[0.30 M]^2[0.30 M]^0[0.30 M]^1$

$k=\frac{9.0\times 10^{-5} M/s}{[0.30 M]^2[0.30 M]^0[0.30 M]^1}$

$k=3.3\times 10^{-3} M^{-2} s^{-1}$

7 0

3 years ago