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madreJ [45]
3 years ago
10

In the reaction K2CrO4(aq) + PbCl2(aq) → 2KCl(aq) + PbCrO4(s), how many grams of PbCrO4 will precipitate out from the reaction b

etween 500.0 milliliters of 3.0 M K2CrO4 in an excess of PbCl2?
Chemistry
2 answers:
svetoff [14.1K]3 years ago
8 0

A.  

1.5 grams

B.  

3.0 grams

C.  

480 grams

D.  

150 grams

are the answer choices...

Ostrovityanka [42]3 years ago
6 0
V=500.0 mL = 0.5 L
c=3.0 mol/L
M(PbCrO₄)=323.2 g/mol

m(PbCrO₄)=M(PbCrO₄)n(PbCrO₄)

m(PbCrO₄)=M(PbCrO₄)n(K₂CrO₄)=M(PbCrO₄)vc

m(PbCrO₄)=323.2*0.5*3.0=484.8 g
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Answer:

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<em>Since the no. of millimoles of HCl is larger than that of KOH. The solution is acidic.</em>

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<em>∴ pH = - log[H⁺] </em>= - log(0.025) = <em>1.602 ≅ 1.60.</em>

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