A small sample of methane burns, releasing 120.0 kJ of heat and doing 830.0 kJ of work. The total energy released is -950.0 kJ.
Energy is a property that is transferred to a physical system, recognizable in the performance of work and in the form of heat and light.
A small sample of methane undergoes combustion. As the hot gas mixture expands, it releases energy (E).
- It releases 120.0 kJ of heat. By convention, when heat is released, we assign it a negative sign. Thus, q = -120.0 kJ.
- It does 830.0 kJ of work. By convention, when the system does work on the surroundings, we assign it a negative sign. Thus, w = -830.0 kJ.
The change in the energy is the sum of the heat released and the work done.
ΔE = q + w = -120.0 kJ + (-830.0 kJ) = -950.0 kJ
A small sample of methane burns, releasing 120.0 kJ of heat and doing 830.0 kJ of work. The total energy released is -950.0 kJ.
Learn more about energy here: brainly.com/question/13881533
Radium is more reactive than calcium so Ra.
The right answer for the question that is being asked and shown above is that: "B 1.5 X 1-^-5 ppm." A 250-mL aqueous solution contains 1.56 mc025-1.jpg 10–5 g of methanol and has a density of 1.03 g/mL. The concentration in ppm is that <span>1.5 X 1-^-5 ppm</span>
Answer:
Double decomposition reaction
Explanation:
When hydrochloric acid reacts with any carbonates/hydrogen carbonates the products formed are metal chloride , water and carbon dioxide.Since HCl decomposes salts of weaker acids.
So the equation of the reaction between calcium carbonate and HCl is:
CaCO3+2HCl =CaCl2+H2O+CO2
This reaction is also known as double decomposition reaction.
