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anyanavicka [17]
3 years ago
11

What distance will be traveled if you are going 120km/hr for 30 min? steps please

Physics
1 answer:
ArbitrLikvidat [17]3 years ago
8 0
D= Speed x Time
Then you convert 120km/hr to m/s depends in wich unifs you want them
120/hr to m/s it's 33.3 m/s and then 30min to seconds it's 1800
D= 33.3m/s(1800s)
D= 59940m
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sammy [17]

Answer:

1.

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6 0
3 years ago
Nuclear energy is over ___ times stronger than the chemical bonds between the atoms
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1 millions times stronger

8 0
3 years ago
A swimming pool is 4.0 m in depth; a swimmer at this depth feels discomfort in the ear. Calculate the net force on a 0.50-cm-dia
Mashcka [7]

The net force on a 0.50-cm-diameter eardrum is mathematically given as

F= 0.76969 N

<h3>What is the net force on a 0.50-cm-diameter eardrum?</h3>

Generally, the equation for Pressure is  mathematically given as

P = ρgh

Therefore

P= 1000*9.8*4

P= 39200 Pa

Where

A= pi*(0.005/2)^2

Generally, the equation for Net force is  mathematically given as

F = PA

F= 39200 *( pi*(0.005/2)^2)

F= 0.76969 N

In conclusion, The net force is

F= 0.76969 N

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5 0
2 years ago
An object moves in one dimensional motion with constant acceleration a = 4.2 m/s^2. At time t = 0 s, the object is at x0 = 3.9 m
solong [7]

Answer:

The object will move to Xfinal = 7.5m

Explanation:

By relating the final velocity of the object and its acceleration, I can obtain the time required to reach this velocity point:

Vf= a × t ⇒ t= (7.2 m/s) / (4.2( m/s^2)) = 1,7143 s

With the equation of the total space traveled and the previously determined time I can obtain the end point of the object on the x-axis:

Xfinal= X0 + /1/2) × a × (t^2) = 3.9m + (1/2) × 4.2( m/s^2) × ((1,7143 s) ^2) =

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8 0
3 years ago
A 2-kg box is pushed by a force of 4 N for 2 seconds. It has an initial velocity vo = 2 m/s to the right. NOTE: Since this probl
IRISSAK [1]

Answer:

Kf= 36 J

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The final kinetic energy Kf

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Initial kinetic energy Ki

Ki = 1/2 m u²

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W(net) = Kf - Ki

W(net) = 36 - 4

W(net) = 32 J

7 0
3 years ago
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