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jeyben [28]
3 years ago
5

If Sheila paid $797.50 in interest on a 5 year loan of $5,800 for her first car, what was the interest rate? (Make sure you’ve c

hanged the decimal to a %)
Mathematics
2 answers:
sveta [45]3 years ago
8 0
5800 times 5 times x percent=797,50
x=797 divide by 5800 times 5 equals 797.5 divided by 29000=0,0275
=2,75 percent

Vsevolod [243]3 years ago
3 0
I = Prt
r = I/Pt
given
I = <span>$797.50
P = </span><span>$5,800
t = 5

so
</span>r = I/Pt
r = 797.50 /  (5,800 x 5)
r = 797.50 / 29,000
r = 0.0275
r = 2.75%

answer
r = 2.75%
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The percent frequency distributions of job satisfaction scores for a sample of information systems (IS) senior executives and mi
tiny-mole [99]

Corrected Question

a. Develop a probability distribution for the job satisfaction score of a senior executive.

b. Develop a probability distribution for the job satisfaction score of a middle manager.

c. What is the probability a senior executive will report a job satisfaction score of 4 or 5?

d. What is the probability a middle manager is very satisfied?

Answer:

(c)0.83

(d)0.28

Step-by-step explanation:

The percent frequency distributions of job satisfaction scores os give below:

\left|\begin{array}{c|c|c}$Job Satisfaction Score&$IS Senior Executives(\%)&$IS Middle Managers(\%)\\1&5&4\\2&9&10\\3&3&12\\4&42&46\\5&41&28\end{array}\right|

(a)Probability distribution for the job satisfaction score of a senior executive.

\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_1(x))\\------&------\\1&0.05\\2&0.09\\3&0.03\\4&0.42\\5&0.41\end{array}\right|

(b)Probability distribution for the job satisfaction score of a middle manager.

\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_2(x))\\1&0.04\\2&0.10\\3&0.12\\4&0.46\\5&0.28\end{array}\right|

(c)Probability a senior executive will report a job satisfaction score of 4 or 5

P(a senior executive will report a job satisfaction score of 4 or 5)

=f_1(4)+f_1(5)\\=0.42+0.41\\=0.83

(d)Probability a middle manager is very satisfied

The probability a middle manager is very satisfied

=f_2(5)\\=0.28

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What is the mean of the values in the dot plot?<br><br><br><br> Enter your answer in the box.
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Answer:

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Step-by-step explanation:

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