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iragen [17]
3 years ago
5

A car is traveling at a constant speed of 23 m/s on a highway. at the instant this car passes an entrance ramp, a second car ent

ers the highway from the ramp. the second car starts from rest and has a constant acceleration. what acceleration must it maintain, so that the two cars meet for the first time at the next exit, which is 3.0 km away?
Physics
1 answer:
spin [16.1K]3 years ago
3 0
23 m/s (dividing by 1000 m/km) = 0.023 km/sDistance (3 km) divided by Speed (0.023 km/s) gives us Time = 130.43478... secSo it takes the first car mentioned about 130 seconds to move from the entrance ramp to the next exit.
We would like the second car to cover the same distance in the same time, but not be traveling at a steady pace, instead start at 0 and constantly increase speed. Even though the speed will be changing each instant, the AVERAGE speed of the second car will be the same as the speed of the first car over those 3 km in order for them to meet again. So the average speed of the second car will be 23 m/s.
Acceleration is a rate of change of speed, (or average speed divided by time). So, to find the acceleration of the second car, we divide 23 m/s by the time 130.43... s. This yields 0.17633333... m/s^2 as the acceleration needed."
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A method of procedure that has characterized natural science since the 17th century, consisting in systematic observation, measurement, and experiment, and the formulation, testing, and modification of hypotheses
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3 years ago
A spotlight on a boat is y = 2.2 m above the water, and the light strikes the water at a point that is x = 8.5 m horizontally di
slava [35]

Answer:

The answer to the question is

The distance d, which locates the point where the light strikes the bottom is   29.345 m from the spotlight.

Explanation:

To solve the question we note that Snell's law states that

The product of the incident index and the sine of the angle of incident is equal to the product of the refractive index and the sine of the angle of refraction

n₁sinθ₁ = n₂sinθ₂

y = 2.2 m and strikes at x = 8.5 m, therefore tanθ₁ = 2.2/8.5 = 0.259 and

θ₁ =  14.511 °

n₁ = 1.0003 = refractive index of air

n₂ = 1.33 = refractive index of water

Therefore sinθ₂ =  \frac{n_1sin\theta_1}{n_2}  = \frac{1.003*0.251}{1.33} = 0.1885 and θ₂ = 10.86 °

Since the water depth is 4.0 m we have tanθ₂ = \frac{4}{x_2} or x₂ = \frac{4}{tan\theta_2 } =\frac{4}{tan(10.86)} = 20.845 m

d = x₂ + 8.5 = 20.845 m + 8.5 m = 29.345 m.

5 0
4 years ago
A resistor R and another resistor 2R are connected in a series across a battery. If heat is produced at a rate of 10W in R, then
alekssr [168]

Answer:

Option B

Solution:

As per the question:

Heat produced at the rate of 10 W  

The resistor R and 2R are in series.

Also, in series, same current, I' passes through each element in the circuit.

Therefore, current is constant in series.

Also,

Power,P' = I'^{2}R

When current, I' is constant, then

P' ∝ R

Thus

\frac{P'}{2R} = \frac{10}{R}

P' = 20 W

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Air has a density of 1.3 kg/m³. Calculate the mass of 36 m³ of air in kilograms. Give your answer to 1 decimal place.
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Answer:

46.8 kg

Explanation:

Mass = (density)(volume)

= (1.3)(36)

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