Answer:
Newton's law of gravitation = statement that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them.
Explanation:
The equation for Newton's Universal Law of gravitation is F=GmM/r^2. Pls brainliest.
Answer:
The answer is C (Higher energy levels)
Explanation:
Because it's C
Answer:
(a) 1.08 m
(b) 1.06 m
Explanation:
<u>Step 1:</u> calculate the center of gravity from 20kg mass
Let the center of gravity from 20kg mass = X
Applying the principle of moment; clockwise moment = ant-clockwise moment
20*X = 35*(1.7-X)
20X = 59.5 - 35X
55X = 59.5
X = 59.5/55
X = 1.08 m
Ignoring the weight of the bar, the center of gravity is 1.08m from left end of the barbell.
<u>Step 2:</u> calculate the center of gravity from 20kg mass, if the 8.0kg mass of the barbell in considered.
Applying the principle of moment
20X +2.353X = 59.5 -35X + 4 - 2.353X
59.706X = 63.5
X = 63.5/59.706
X = 1.06 m
considering the weight of the bar, the center of gravity is 1.06m from left end of the barbell.
Answer:
So, we can assemble the options based or evaluation of there properties regarding getting an equilibrium or balanced state in a given time.We have the following rankings attributed to the elements:
- Silveringpot≥ aluminiumpot ≥ironskillet ≥glasscasseroldish ≥welldone steak ≥woodencuttingboard.
Explanation:
<u>Attaining equilibrium matters:</u>
When the materials are placed inside the oven, they attain a high temperature value causing it to be non touchable but some of the items has low value to attain the equilibrium state when comes in contact with other mediums. As these materials are also arranged based on that analyses.
Answer:
(a) 0.177 m
(b) 16.491 s
(c) 25 cycles
Explanation:
(a)
Distance between the maximum and the minimum of the wave = 2A ............ Equation 1
Where A = amplitude of the wave.
Given: A = 0.0885 m,
Distance between the maximum and the minimum of the wave = (2×0.0885) m
Distance between the maximum and the minimum of the wave = 0.177 m.
(b)
T = 1/f ...................... Equation 2.
Where T = period, f = frequency.
Given: f = 4.31 Hz
T = 1/4.31
T = 0.23 s.
If 1 cycle pass through the stationary observer for 0.23 s.
Then, 71.7 cycles will pass through the stationary observer for (0.23×71.7) s.
= 16.491 s.
(c)
If 1.21 m contains 1 cycle,
Then, 30.7 m will contain (30.7×1)/1.21
= 25.37 cycles
Approximately 25 cycles.
