Using the 3rd equation of motion:
= v² - u² = 2gs ------ [g = Acceleration due to gravity]
= v² - 20² = 2 × 10 × 300
= v² - 400 = 6000
= v² = 6000 - 400
= v = √5600
= v = 74.83 m/s
And yeah it's done :)
For the work-energy theorem, the work needed to stop the bus is equal to its variation of kinetic energy:

where
W is the work
Kf is the final kinetic energy of the bus
Ki is the initial kinetic energy of the bus
Since the bus comes at rest, its final kinetic energy is zero:

, so the work done by the brakes to stop the bus is

And the work done is negative, because the force applied by the brake is in the opposite direction to that of the bus motion.
it's how much it weighs and how much force is pushing on it like a egg if i drop it the weigh can cause it to break and how much force the gravity is pushing on it.
The first ariplanr was made December 17, 1903