1. Find the force of friction between the sports car and the station wagon stuck together and the road. The total mass m = 1928kg + 1041kg = 2969kg. The only force in the x-direction is friction: F = μ*N = μ * m * g
2. Find the acceleration due to friction:
F = m*a = μ * m * g => a = μ * g = 0.6 * 9.81
3. Find the time it took the two cars stuck together to slide 12m:
x = 0.5*a*t²
t = sqrt(2*x / a) = sqrt(2 * x / (μ * g) )
4. Find the initial velocity of the two cars:
v = a*t = μ * g * sqrt(2 * x / (μ * g) ) = sqrt( 2 * x * μ * g)
5. Use the initial velocity of the two cars combined to find the velocity of the sports car. Momentum must be conserved:

m₁ mass of sports car
v₁ velocity of sports car before the crash
m₂ mass of station wagon
v₂ velocity of station wagon before the crash = 0
v velocity after the crash

m₁*v₁ + m₂*v₂ = (m₁+m₂) * v = m₁*v₁
v₁ = (m₁+m₂) * v / m₁ = (m₁+m₂) * sqrt( 2 * x * μ * g) / m₁
v₁ = 33.9 m/s

7 0

3 years ago

A cylindrical metal specimen 10.7000 mm in diameter and 95.000 mm long is to be subjected to a tensile force of 6300 N; at this

marta [7]

Answer:

a) Y = 4.16 10¹⁰ N / m² , b) B= 37.4 10¹⁰ Pa

Explanation:

a) For this exercise we must use the Young's modulus formula

Y = P / DL / L

We look for the magnitude salt system SI

d₁ = 10.7000 mm = 10.7000 10⁻³ m

l₁ = 95,000 mm = 95,000 10⁻³ m

l₂ = 95.040 mm = 95.040 10⁻³ m

d₂ = 10.698 mm = 10.698 10⁻³ m

The pressure is

P = F / A

A = π r²

P = F / pi r²

P = 6300 / π (10.7 10⁻³)²

P = 17,5155 10⁶ Pa.

Change in length

ΔL = l₂-l₁

ΔL = (95.04000 -95.000) 10⁻³

ΔL = 0.040 10⁻³ m

Let's calculate

Y = 17,515 10⁶ 95,000 10⁻³ / 0.040 10⁻³

Y = 4.16 10¹⁰ N / m²

This Young or elasticity module is very close to the medium density fiberboard or solid poly styrene module

b) If in addition to the length the diameter also changes, the whole body volume changes, so we can use the ratio of the volume module

B = -P / DV / V

Let's look for the initial volume of the cylinder

V₁ = π r₁² l₁

r₁ = d₁ / 2 = 10.7000 10⁻³ / 2

r₁ = 5.3500 10⁻³ m

r₂ = 10.698 / 2 10⁻³

r₂ = 5.349 10⁻³ m

V₁ = π (5.35 10⁻³)² 95.00 10⁻³

V₁ = 8.5424 10⁻⁶ m³

Let's calculate the final volume

V₂ = π r₂² L₂

V₂ = π 5.349² 10⁻⁶ 95.040 10⁻³

V₂ = 8.54282 10⁻⁶ m³

Let's look for the volume change

ΔV = V₂ - V₁

ΔV = (8.54280 - 8.5424) 10⁻⁶

ΔV = 0.0004 10⁻⁶ m³

Let's calculate the Bulk module

B = 17,515 10⁶ 8.5424 10⁻⁶ /(0,0004 10⁻⁶)

B = 3.74 10¹¹ Pa

B= 37.4 10¹⁰ Pa

This volume module corresponds to some type of glass made with poly styrene

5 0

3 years ago

In addition to telling you which programs are currently running, what other information does the task bar display?

uysha [10]

The Task bar is the bar that(For the most part) is on the bottom of most computers.

The answer is A - The Current Time

4 0

3 years ago

Read 2 more answers