Answer:
hello your question is not properly structured below is the complete question
. Consider the discussion in Section 1.3 of packet switching versus circuit switching in which an example is provided with a 1 Mbps link. Users are generating data at a rate of 100 kbps when busy, but are busy generating data only with probability . Suppose that the 1 Mbps link is replaced by a 1 Gbps link. a. What is N, the maximum number of users that can be supported simultaneously under circuit switching?
answer : N = 1000 users
Explanation:
The maximum number of users (n) that can be supported simultaneously under circuit switching
N = Total transmission / rate of data generation by users
Total transmission = 1 Gbps = 1 * 10^9 bps
rate of data generation by user = 100 kbps = 10 * 10^4 bps
hence the maximum number of users that can be supported simultaneously
= ( (1* 10^9) / (10 * 10^4) )
= 10000 users
So the air evaporate s and mix the temptures and marks air power to the same theme as the other the two degrees lower and lower until they are the same
Pressure = Force / area = 100 / 2 = 50 N/m^2
If the area is a 2x2 = 4m^2 then pressure = 100/4 = 25 N/m^2
(Not Clear what the area is from your question)
2.4g
explanation: mass/volume=density
36/15=2.4
Answer:
Option f is true. cannot tell since we need to know the distance between two charges
Explanation:
Distance between two charges is a factor in the force between them that is F = m * A = (k * q1 * q2)/ r²
Where f = force , m= acceleration, a = acceleration, k = constant, q1 and q2 = charges, r = distance between the two charges.
Since r is not giving , magnitude of acceleration can't be determined.