Which of the following is the correct scientific notation for 0.000056?

tyrosine kinase inhibitor binds and inhibits BTK. As a result of the experiment, you are able to elute BTK from the column, but

Sindrei [870]

Answer: It is because tyrosine kinases and BTK have similar solubilities

Explanation:

In column chromatography, components of a mixture are seperated based on their relative solubilities in two non-mixing phases.

In essence, tyrosine kinases and BTK are present in the eluate due to their similar solubility rates that arise from the similar chemical structure both possess (otherwise it would be impossible for the inhibitor meant for Tyrosine kinase to bind and also inhibits BTK)

Thus, the similar solubilities of both groups is the reason they could elute out of the column without being adsorped.

3 0

3 years ago

What is the mass of 8.12 x 10^23 molecules of co2

Over [174]

Answer:

Explanation:

Mole = no. Molecules/6.02×10^23

Mole = (8.12×10^23)/(6.02×10^23)

Mole = 1.35mole

Molar mass of CO2 = 12+ 2(16)

Molar mass= 12 + 32= 44g/mol

Mole = mass/molar mass

Mass = Mole × molar mass

Mass = 1.35× 44

Mass= 59.35g

4 0

3 years ago

If a compound has 24.0g of carbon, 6.0g of hydrogen, and 16.0g of oxygen what is its

nikklg [1K]

Answer:

CH2

Explanation:

What is the empirical formula of a compound that contains 20.0g carbon and 3.37g hydrogen? Divide by the smallest number of moles. The empirical formula is CH2.

4 0

2 years ago

The large bulb, with a volume of 6.00 L, contains nitric oxide at a pressure of 0.500 atm, and the small bulb, with a volume of

NISA [10]

Answer:

P(O2) = 0.300 atm

P(NO2) = 0.400 atm

P(NO) = 0 atm

Explanation:

Step 1: Data given

Volume of large bulb = 6.00L

Large bulb contains nitric oxide at 0.500 atm

Volume of the small bulb = 1.50 L

Small bulb contains oxygen at 2/50 atm

The initial temperature = 22.0°C

Step 2: The balanced equation

2 NO + O2 → 2 NO2

Step 3: Calculate moles of NO

P*V=n*R*T

n = (P*V)/(R*T)

⇒ with P = the pressure of NO = 0.500 atm

⇒ with V = the volume of NO = 6.00L

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 22.0 °C = 295 K

⇒ with n = the number of moles of NO

n(NO) = (0.500 *6.00)/(0.08206*295)

n(NO) = 0.124 moles

Step 4: Calculate moles of O2

n = (P*V)/(R*T)

⇒ with P = the pressure of O2 = 2.50 atm

⇒ with V = the volume of 02 = 1.50 L

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 22.0 °C = 295 K

⇒ with n = the number of moles of O2

n(O2) = (2.50*1.50)/(0.08206*295)

n(O2) = 0.155 moles

Step 5: Calculate the limiting reactant

For 2 moles NO consumed, we need 1 mole O2 to produce 2 moles of NO2

No is the limiting reactant. It will completely be consumed. (0.124 moles)

O2 is in excess. There will react 0.124/2 = 0.062 moles O2

There will remain 0.155 - 0.062 = 0.093 moles O2

Step 6: Calculate moles of NO2

For 2 moles NO consumed, we need 1 mole O2 to produce 2 moles of NO2

For 0.124 moles NO, we'll have 0.124 moles NO2

Step 7: Calculate partial pressure of O2

P*V= n*R*T

P = (n*R*T) / V

⇒ n = the number of moles O2 = 0.093 moles O2 remain

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 295 Kelvin

⇒ V = the volume = 6.00 + 1.50 = 7.50 L

P(O2) = 0.300 atm

Step 8: Calculate partial pressure of NO2

P = (n*R*T) / V

⇒ n = the number of moles NO2 = 0.124 moles

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature = 295 Kelvin

⇒ V = the volume = 6.00 + 1.50 = 7.50 L

P(NO2) = 0.400 atm

P(NO) = 0 atm because NO is completely consumed.

7 0

3 years ago

Which of the following provides an instantaneous measure of radioactivity:

Nikitich [7]

Answer:

Option 2 is correct.

Scintillation counters and Geiger Counters provide instantaneous measure of radioactivity.

Explanation:

Of the three means of measuring radioactivity presented. Only Film-badge dosimeter lacks a sensitive photo-detector piece that instantaneously converts the amount of radiation seen into electrical waves. It collects the radiation over time and the film is then developed after a particular point in time for the radioactivity collected to be measured.

Although used majorly for gamma rays and neutrons, the scintillation counters uses a scintillator to convert ionizing radiation (like the two mentioned at the start of this passage), into photons that the photo-detector (usually very sensitive) converts into electrical signals for immediate reading. It gives the energy and intensity of the radiation intended to.be measured.

The Geiger Muller counter, the most used measure of radioactivity across all fields, uses the tube (which contains inert gases) as the sensitive radiation detecting piece. High voltage maintained in the tube makes the gases conductive and it transmits the intemsity of radiation to the processing part of the counter which converts this reading to electrical signals, immediately for reading. Unlike the scintillation counters, it doesn't measure the energy of the radiation.

Hope this Helps!!!

5 0

3 years ago

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